Answer:
the only one of these materials that allows studying processes of a very long period of time is Uranium 238
Explanation:
In a radioactive material, half of the atoms decay each life period, in carbon 14 this period T = 5730 years, so for a time of 40,000 years there are 7 life periods, so there are very few atoms left without decomposing .
To study older samples, materials with a longer life period are needed, let's show the visa time
²³⁸U T= 4.5 10¹⁰ years
⁹¹Rb T = 58 s
¹³¹I T= 8.04 days
⁶⁰Co T= 5.27 years
Therefore, the only one of these materials that allows studying processes of a very long period of time is Uranium 238
Answer:
-0.10472
Explanation:
Remember that any <u><em>clockwise</em></u> rotation is considered negative, and any <u><em>counterclockwise</em></u> rotation is considered positive.
The formula for period is:
Solve for and you get:
The period is 60 seconds so make that division and you're left with -0.10472 or -0.10 if significant figures apply (negative because the rotation is clockwise).
You've built quite a convoluted question there, Thelo.
If you wrote what you mean and I read it correctly, then the phrase
in the blank is "... the loss of energy to friction in the machine ...".
Answer:768.75N
Explanation:
mass=62.5kg
acceleration=12.3m/s^2
Force=mass x acceleration
Force=62.5 x 12.3
Force=768.75N
Energy. Hope it helps! :)