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Lena [83]
3 years ago
14

Carbon-14 is the typical radioisotope used to date materials; however, it has a limitation to 40,000 years. A scientist who want

s to date materials older than 40,000 years would most likely use which radioisotope? uranium-238 rubidium-91 iodine-131 cobalt-60
Physics
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

the only one of these materials that allows studying processes of a very long period of time is Uranium 238

Explanation:

In a radioactive material, half of the atoms decay each life period, in carbon 14 this period T = 5730 years, so for a time of 40,000 years there are 7 life periods, so there are very few atoms left without decomposing .

To study older samples, materials with a longer life period are needed, let's show the visa time

²³⁸U     T=  4.5 10¹⁰ years

⁹¹Rb     T =  58 s

¹³¹I        T= 8.04 days

⁶⁰Co     T= 5.27 years

Therefore, the only one of these materials that allows studying processes of a very long period of time is Uranium 238

ASHA 777 [7]3 years ago
5 0

Answer:

A) Uranium-238 is the correct answer.

You might be interested in
A ballistic pendulum is a device for measuring bullet speeds. One of the simplest versions consists of a block of wood hanging f
jeka94

Answer:

0.043 m upwards

Explanation:

The mass of the bullet, $m_1$ = 0.013 kg

Mass of the ballistic pendulum, $m_2$ = 3 kg

Velocity of the bullet, $v_1$ = 320 m/s

Therefore, from the law of conservation of momentum, we get

$m_1v_1+m_2v_2=m_1v_1^1+m_2v_2^1$

$(0.013 \times 320)+(3 \times 0) = \left(0.013 \times \frac{320}{0}\right) + (3 \times v_2^1)$

$3 \times v_2^1=2.774$

$v_2^1=0.92 \ m/s$

Therefore the required height to rise the block is given by :

$(v_2^1)^2-v_2^2=2gh$

$h=\frac{(v_2^1)^2-v_2^2}{2g}$

$h=\frac{(0.92)^2-0}{2(-9.81)}$

$h=-0.043 \ m$

Therefore, the block moves upwards for 0.043 meters.      

5 0
3 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s.A violinist is tuning her instrument to concert A
Molodets [167]

Answer:

A) 443 Hz

B) She has to loosen the string

Explanation:

A) Given;

Beat frequency;f_beat = 3 Hz

Frequency of electronically generated tone; f_e = 440 Hz

We know that formula for beat frequency is given by;

f_beat = |f1 - f2|

Now, applying it to this question, we have;

f_beat = f_v - f_e

Where f_v is frequency of the note played by the violinist

Thus, plugging in the relevant values;

3 = f_v - 440

f_v = 3 + 440

f_v = 443 Hz

B) In the concept of wave travelling in a string, the frequency is directly proportional to the square root of the force acting on the string.

Now, for the violinist to get her violin perfectly tuned to concert A from what it was when she heard the 3-Hz beats, the beat frequency will have to be zero. Which means it has to decrease by 3 Hz. For it to decrease, it means that the force applied has to decrease as we have seen that frequency is directly proportional to the square root of the force acting on the string.

Thus, she would have to loosen the string.

7 0
4 years ago
If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 26m/s, how far would she
svetlana [45]

Answer:

34.45m

Explanation:

Using the equation of motion formula v² = u²+2as to get the distance travelled

v is the final velocity = 26m/s

u is the initial velocity = 0m/s

a is the acceleration due to gravity = 9.81m/s²

S is the distance travelled

Substituting the given values into the formula;

26² = 0²+2(9.81)s

676 = 0 + 19.62s

19.62s = 676

s = 676/19.62

s = 34.45m

Hence the distance she would travel during the race is 34.45m

7 0
3 years ago
Suppose you and a friend are test driving a new car. You drive out of the car dealership and go 10 miles east and then 8 miles s
damaskus [11]

a =12miles

b =10miles

ab =2miles

Explanation:

at first the car is drown out of dealership and went 10 miles east and then 8 miles south

then your friend drives 8 miles west and 6 miles north.

then the distance it flies to get back to dealership is

10²+8 ²=12miles

8²+6²=10miles

12-10= 2 miles

5 0
3 years ago
What is the fastest motion that can be measured in any frame of reference?
Furkat [3]

Answer: The answer is D: 300,000km/s

Explanation:

7 0
3 years ago
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