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Dovator [93]
3 years ago
12

The periodic table lists all the compounds on Earth. True or False?

Physics
1 answer:
In-s [12.5K]3 years ago
8 0
False. Maybe you were talking about elements? If these were elements then the answer could be TRUE.
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What are the name of variables that do not change through out and experiment?
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The answer is C

Explanation:

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A ball is thrown straight up in the air, as it rises, will its velocity increase, decrease or remain the same? Will its accelara
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Free fall condition : acceleration is constant downward and equals to gravitational acc.(g)

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The deflection of alpha particles in rutherford’s gold foil experiments resulted in what change to the atomic model? the additio
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Three students attempt to define what it means for lines lll and mmm to be perpendicular. Can you match the teacher's comments t
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Incompletevquestion. However, I inferred from a general perspective about perpendicular lines.

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3 0
3 years ago
A 2000-kg truck is being used to lift a 400-kg boulder B that is on a 50-kg pallet A. Knowing the acceleration of the rear-wheel
anzhelika [568]

Answer:

(a) reaction at each front wheel is 5272N (upward)

(b) force between boulder and pallet is 4124N (compression)

Explanation:

Acceleration of the truck a_{t = 1 m/s^{2}  (to the left)

when the truck moves 1 m to the left, the boulder is B and pallet A are raised 0.5 m, then,

a_{A} =  0.5 m/s^{2} (upward) , a_{B} =  0.5 m/s^{2} (upward)

Let T be tension in the cable

pallet and boulder: ∑fy = ∑(fy)eff = 2T- (m_{A} + m_{B})g =  (m_{A} + m_{B})a_{B}

                                  = 2T- (400 + 50)*(9.81 m/s^{2}) = (400 + 50)*(0.5 m/s^{2})

                        T = 2320N

Truck:  M_{R} = ∑(M_{R})eff: = -N_{f} (3.4m) + m_{T} (2.0m) - T (0.6m)= m_{T} a_{T} (1.0m)

Nf = (2.0m)(2000 kg)(9.81 m/s^{2} )/3.4m -  (0.6 m)(2320 N)/3.4m + (1.0 m)(2000 kg)(1.0 m/s^{2})  = 11541.2N - 409.4N - 588.2N = 10544N

∑fy (upward) = ∑(fy)eff: N_{f} + N_{R} - m_{T}g = 0

                                       10544 + N_{R}  - (2000kg)(9.81 m/s^{2} ) = 0

                N_{R} = 9076N

   ∑fx (to the left) = ∑(fx)eff:  F_{R} - T = m_{T} a_{T}

                                      F_{R} = 2320N + (2000kg)(9.81 m/s^{2} ) = 4320N

(a) reaction at each front wheel:

1/2 N_{f} (upward): 1/2 (10544N) = 5272N (upward)

(b) force between boulder and pallet:

∑fy (upward) = ∑(fy)eff: N_{B} + M_{B}g - m_{B}a_{B}

            N_{B} = (400kg)(9.81 m/s^{2}) + (400kg)(0.5 m/s^{2}) = 4124N (compression)

3 0
4 years ago
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