Question

Any Acellus folk figure out the answer to this one??? I CANNOT for the life of me.

Answer 1

Answer:

-0.10472$\frac{rad}{s}$

Explanation:

Remember that any clockwise rotation is considered negative, and any counterclockwise rotation is considered positive.

The formula for period is:

$T = \dfrac{2\pi}{\omega}$

Solve for $\omega$ and you get:

$\omega=\dfrac{2\pi}{T}$

The period is 60 seconds so make that division and you're left with -0.10472$\frac{rad}{s}$ or -0.10$\frac{rad}{s}$ if significant figures apply (negative because the rotation is clockwise).