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Harman [31]
3 years ago
5

Evaluate 8b/b+a when a=4 and b=5

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

40/9 or 4.444444

Step-by-step explanation:

a = 4  b = 5

8b/b + a

8(5)/b + a

40/b + a

40/ 5 + 4

Answer = 40/9

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4 years ago
The third through the fifth terms of a geometric sequence are given by a3 = 18, a4 = 27 , and a5 = 81/2
Kaylis [27]

Let <em>a</em> be the first term in the sequence. If <em>r</em> is the ratio between consecutive terms, then the second term is <em>ar</em>, the third term is <em>ar </em>^2, the fourth is <em>ar</em> ^3, and so on, up to the <em>n</em>-th term <em>ar</em> ^(<em>n</em> - 1).

So the third, fourth, and fifth terms are such that

<em>ar</em> ^2 = 18

<em>ar</em> ^3 = 27

<em>ar</em> ^4 = 81/2

Solve for <em>a</em> and <em>r</em> :

(<em>ar</em> ^3) / (<em>ar</em> ^2) = 27/18   =>   <em>r</em> = 3/2

<em>ar</em> ^2 = <em>a</em> (3/2)^2 = 9/4 <em>a</em> = 18   =>   <em>a</em> = 8

Then the <em>n</em>-th term in the sequence is

<em>ar</em> ^(<em>n</em> - 1) = 9 (3/2)^(<em>n</em> - 1)

You can rewrite this by first rewriting 9 = 3^2, then

9 (3/2)^(<em>n</em> - 1) = 3^2 * 3^(<em>n</em> - 1) / 2^(<em>n</em> - 1) = 3^(<em>n</em> + 1)/2^(<em>n</em> - 1)

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3 years ago
Solve this equation <br><br> 7b-6(11-2b)=10
Mkey [24]
7b-6(11-2b)=10
The first step is to distribute. Multiply each number inside the parentheses by -6.
7b + (-6*11) + (-6*-2b) = 10
7b - 66 + 12b = 10

Now combine like terms.
19b - 66 = 10

Add 66 to both sides.
19b = 76

Divide both sides by 19.
b = 4

The answer is b = 4.
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mafiozo [28]

Answer:

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Step-by-step explanation:

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3 years ago
In a school with 400 students 22% of them are 6th grade how many students are in 6th grade​
Serjik [45]

Answer:

88

Step-by-step explanation:

400*0.22 gives the answer

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4 years ago
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