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3 years ago

Pleaseeeeeeeeee help DO ALL 3 PLEASE AND THANK YOU

Mathematics

1 answer:

juin [17]3 years ago

3 0

Answer:

Its 10,780 then 7,278 and I dont think I know the last one

Step-by-step explanation:

(Sorry if that's wrong I didn't really get it fully, hope this helps)

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PLEASE HELP<br>L has y-intercept (0,5) and is perpendicular to the line with equation y=1/3x+1

marin [14]

Answer:

y=-3x+5

Explanation:

Given a line L such that:

• L has y-intercept (0,5); and

• L is perpendicular to the line with equation y=(1/3)x+1.

We want to find the equation of the line in the slope-intercept form.

The slope-intercept form of the equation of a straight line is given as:

$\begin{equation} y=mx+b\text{ where }\begin{cases}m={slope} \\ b={y-intercept}\end{cases} \end{equation}$

Comparing the given line with the form above:

$y=\frac{1}{3}x+1\implies Slope,m=\frac{1}{3}$

Next, we find the slope of the perpendicular line L.

• Two lines are perpendicular if the product of their slopes is -1.

Let the slope of L = m1.

Since L and y=(1/3)x+1 are perpendicular, therefore:

$\begin{gathered} m_1\times\frac{1}{3}=-1 \\ \implies Slope\text{ of line L}=-3 \end{gathered}$

The y-intercept of L is at (0,5), therefore:

$y-intercept,b=5$

Substitute the slope, m=-3, and y-intercept, b=5 into the slope-intercept form.

$\begin{gathered} y=mx+b \\ y=-3x+5 \end{gathered}$

The equation of line L is:

$y=-3x+5$

7 0

1 year ago

Cuantos parque solares hay en china

emmainna [20.7K]

The translation of the question is:

<h3>What are solar parks?</h3>

The solar park is a concentrated zone of development of solar power generation projects and provides developers an area that is well characterized, with proper infrastructure and access to amenities and where the risk of the projects can be minimized.

How many solar parks are there in China?

Huanghe Hydropower Hainan Solar Park – 2.2GW
Tengger Desert Solar Park – 1.55GW
Datong Solar Power Top Runner Base – 1.1GW
Yanchi Ningxia Solar Park – 1GW
Longyangxia Dam Solar Park – 850MW

Learn more about solar energy here:

brainly.com/question/9704099

#SPJ1

7 0

2 years ago

Rewrite as y−k=a(x−h)2 or x−h=a(y−k)2. Find the vertex, focus, and directrix.<br> y−3=(2−x)^2

Talja [164]

Given:

The given equation is

$y-3=(2-x)^2$

To find:

The vertex, focus, and directrix.

Solution:

The equation of a parabola is

$y-k=a(x-h)^2$ ...(i)

where, (h,k) is vertex, $\left(h,k+\dfrac{1}{4a}\right)$ and directrix is $y=k-\dfrac{1}{4a}$

We have,

$y-3=(2-x)^2$

It can be written as

$y-3=(-(x-2))^2$

$y-3=(x-2)^2$ ...(ii)

On comparing (i) and (ii), we get

$h=2,k=3,a=1$

Vertex of the parabola is (2,3).

$Focus=\left(2,3+\dfrac{1}{4(1)}\right)$

$Focus=\left(2,3+\dfrac{1}{4}\right)$

$Focus=\left(2,\dfrac{13}{4}\right)$

Therefore, the focus of the parabola is $\left(2,\dfrac{13}{4}\right)$ .

Directrix of the parabola is

$y=3-\dfrac{1}{4(1)}$

$y=3-\dfrac{1}{4}$

$y=\dfrac{11}{4}$

Therefore, the directrix of the parabola is $y=\dfrac{11}{4}$ .

4 0

3 years ago

Help! Due in 5 minutes

Flauer [41]

The first one is 2/3
Second one is 1/3 2/3 and 3/3
Last one is may be because they are equal?

6 0

3 years ago

Restrict the domain of the function f(x) = (x-2)^2 so it has an inverse. Then determine its inverse function.

san4es73 [151]

Answer:

Look to the bold answer down

Step-by-step explanation:

* Lets explain how to restrict the domain of the quadratic function

- The quadratic function is two-to-one function

- The inverse of it is one-to-two which is not a function

- So we can not find the inverse of the quadratic function until restrict its

domain

- We restrict the domain at the x-coordinate of the vertex of the function

∵ f(x) = (x - h)² + k is the standard form of the quadratic function, where

(h , k) are the coordinates of its vertex

- To restrict the domain we put x > h for the right part of the parabola

or x < h for the left part of the parabola

* Lets solve the problem

∵ f(x) = (x - 2)²

∵ f(x) = (x - h)² + k is the standard form of the quadratic function

∴ h = 2 and k = 0

∴ The vertex of the parabola is (2 , 0)

- We will restrict the domain at x = 2

∴ The domain of the function f(x) to have inverse is x > 2 or x < 2

* The restriction domain is x > 2 or x < 2

- To find the inverse of the function switch x and y and solve for the

new y

∵ f(x) = (x - 2)²

∵ f(x) = y

∴ y = (x - 2)²

- Switch x and y

∴ x = (y - 2)²

- take square root for both sides

∴ ± √x = y - 2

- Add 2 for both sides

∴ ± √x + 2 = y

∴ $f^{-1}=\sqrt{x}+2=====OR=====f^{-1}=-\sqrt{x}+2$

* For the domain x > 2 of f(x) the inverse is $f^{-1}(x) = \sqrt{x}+2$

For the domain x < 2 of f(x) the inverse is $f^{-1}(x)=-\sqrt{x}+2$

7 0

3 years ago