All categories

2 years ago

Jabes travelled 3406km in 8days. if he travelled the same distance every day, how many kilometers did he travel per day?

Mathematics

1 answer:

lisabon 2012 [21]2 years ago

8 0

Jabes travels 425.75km per day.

Unit rate is the amount of a certain item related to a single unit of another item.

In the question, we are given that Jabes traveled 3406km in 8 days

We have to find the distances that Jabes travel per day which will be the unit rate of distance per day.

The total distance that jabes traveled in 8 days = 3406 km

Thus, the distance per day jabes traveled can be calculated as:

8 days ⇒3406 km

or, 1 day⇒ 3406/8days = 425.75km

Thus,jabes traveled 425.75 km per day, using the unit rate.

Learn more about the unit rate here:

brainly.com/question/4895463

#SPJ4

You might be interested in

Find the geometric mean of 125 and 5

kramer

Answer:

Step-by-step explanation:

7 0

4 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

Please help I’ll make you the brainiest

egoroff_w [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Prove the divisibility of the following numbers:

yan [13]

$8^{10}-8^9-8^8=8^8(8^2-8-1)=8^8(55)$

$81^7-27^9-9^{13}=3^{28}-3^{27}-3^{26}=3^{26}(3^2-3-1)=3^{26}(5)=3^{24}(45)$

8 0

3 years ago

Graph the line y=kx+1 if it is known that the point M belongs to it: m(1,3)

Novosadov [1.4K]

Answer:

y = 2x +1

Step-by-step explanation:

y=kx+1

Substitute the point into the equation

3 = k(1) + 1

3 = k+1

Subtract 1 from each side

3-1 = k

2 = k

y = 2x +1

The slope is 2 and the y intercept is 1

3 0

3 years ago

Read 2 more answers