All categories

3 years ago

Which of the following are true of a regular pentagon?

1 answer:

6 0

Each angle measure is 108°. <-------------------- this is true
The angle sum is 720°.
It has six sides.
It is equilateral. <--------------------------------------- this is true

i hope i helped

You might be interested in

Determine the slope (m) and y-intercept (b) of the line: Y = 1/2 X + 1

Sladkaya [172]

Answer:

i thik it is the last one

Step-by-step explanation:

3 0

3 years ago

Find the derivative of the inverse function of the original function f(x)=(x+1)^3-5

____ [38]

Answer:

Step-by-step explanation:

let f(x)=y

$y=(x+1)^{3} -5\\flip ~x~and~y\\x=(y+1)^{3}-5\\(y+1)^{3}=x+5\\y=(x+5)^{\frac{1}{3} } -1\\or~f^{-1}(x)=(x+5)^{\frac{1}{3} } -1\\(f^{-1})'(x)=\frac{1}{3} (x+5)^{\frac{-2}{3} }$

4 0

3 years ago

Lisa has a certain amount of money. She spent 39 dollars and has 3/4th of the original amount left. How much money did she have

harina [27]

If $\frac { 3 }{ 4 }$ is left, that means $\frac { 1 }{ 4 }$ was spent. So $\frac { 1 }{ 4 }$ of the total amount is equal to 39.. Let's say x to the total amount. $\frac { 1 }{ 4 } \cdot x=39\\ x=4\cdot 39\\ x=156\\$

4 0

3 years ago

Read 2 more answers

Which equation represents a circle that contains the point (-5,-3) and has a center at (-2,1)

MatroZZZ [7]

Answer:

The equation of circle is:

Solution:

The general form of equation is given as:

Where, "r" is radius of circle and (a, b) is center of circle

Given that center at (-2, 1)

a = -2 and b = 1

Substitute (a , b) = (-2, 1) and (x, y) = (-5, -3) in general equation

Substitute r = 5 and (a, b) = (-2, 1) in general equation

Thus the equation of circle is found

4 0

3 years ago

Mind helping me find the rate of change and y intercept???

irga5000 [103]

Answer:

gradient is 8 and y intercept is 0

Step-by-step explanation:

y=mc+b

take one pair of corridants:

8=1m+b

m=8 (change in y values/changes in x values)

8=1x8+b

do the equation

y=0

Have a nice day!!!!!!!!! :-)

KA

5 0

3 years ago