Bacteria exposed to DNA can incorporate the DNA and change phenotype.
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Chromatids thats your answer to that question.
Here’s the answer:
Schwann Cells
Answer: 0.18
Explanation:
For the alleles, the percentage distribution of each is 'A' (90% = 0.9)
While 'a' (10% = 0.1)
Hence, 0.9 and 0.1 are the respective frequencies of each allele
Now, apply Hardy-Weinberg Equilibrium equation, where heterozygotes are represented by the 2pq term.
Therefore, the number of heterozygous individuals (Aa) is equal to 2pq which equals
2 × 0.9 × 0.1 = 0.18
Thus, the frequency of heterozygote is 0.18, while the percentage distribution in the population is 18%
Answer:
let the three parts be
5x + 3x + 4x = 250
so on adding
12x = 250
x = 20
so it will be divided into three parts as
5 × 20 = 100
3×20= 60
4×20 = 80
Explanation:
