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timama [110]
3 years ago
13

I need help please! I will mark brainliest if you are correct

Mathematics
2 answers:
tatiyna3 years ago
5 0

Answer:  its AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

pashok25 [27]3 years ago
5 0

Answer:

I'm pretty sure there is two if I'm wrong correct me!

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9/10 ÷ 5/10<br> can you please explain?
frozen [14]

Answer:

Step-by-step explanation:

Hello,

Dividing by 1/2 is like multiplying par 2, right ?

Dividing by 5/10 is like multiplying par 10/5, right ?

and then

\dfrac{\dfrac{9}{10}}{\dfrac{5}{10}}=\dfrac{9}{10}\times \dfrac{10}{5}=\dfrac{9}{5}

as 10/10=1

Thanks

3 0
3 years ago
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Which of these sequences are arithmetic? Check all that apply.
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I know that the second one the fourth one and the fifth one are arithmetic but I’m not sure about the others I think there are only three but don’t count me on it
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3 years ago
Find three solutions of the equation y = 9x - 4.
Darina [25.2K]
First one; substitute x into the equation and see if the result equal y in the coordinate 
7 0
4 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
What are the values of x ?
Vera_Pavlovna [14]

Answer:

50

Step-by-step explanation:

since they are parallel then 2x+6=106

so subtract 6 from each side so it's 2x = 100

then divide each since by 2

so x= 50

7 0
3 years ago
Read 2 more answers
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