Given that there are <span>6 boys and 6 girls in a birthday party, the number of different arrangements of</span><span> first, second, and third is given by:

$^{12}P_3= \frac{12!}{(12-3)!} \\ \\ = \frac{12!}{9!} = \frac{12\times11\times10\times9!}{9!} \\ \\ =12\times11\times10=1,320$ </span>

7 0

3 years ago

You roll a fair 6 sided die what is P roll less than 4

Veseljchak [2.6K]

Answer:

1/2

Step-by-step explanation:

Die : 1,2,3,4,5,6

Less than 4: 1,2,3

P (less than 4) = Number of options less than 4/ total

= 3 /6

=1/2

7 0

4 years ago

Pls help asap! thanks

shtirl [24]

Answer:

Try 3 x -6.3 + 2 x 5

6 0

3 years ago

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