Dont know if its right but :/ <span>NiS <---> Ni+2 + S-2 </span><span>Ksp = [Ni+2] * [S-2] = (9.6E=11)^2 = 9.22E-21</span>
Answer:
k
Explanation:
electron affinity (EA) depends on various factors like effective nuclear charge (enc) , size of the atom, ellipticity of sub-shell (ep) , nature of configuration.
more is the enc more will be the EA
more is the size less will be the EA
more valance shell ellipticity (closer to the nuclei) more will the EA ( all given element posses P orbital in the valance shell)
Answer:
ΔP = -3556.36 Pa
Explanation:
Atmospheric pressure, P = 101300 Pa
Latent heat of boiling water, 
Boiling point at atmospheric pressure, T = 373.15 K
ΔT = 1 K
The change in volume as the water boils to vapor will be
Since the volume of vapor (
) is far greater than the volume of liquid (
)
Using the ideal gas equation:
R = 8.314 J/mol-K
ΔV = 0.0306 m³
Molecular weight of water, MW = 0.018 kg/mol
Using the Clausius - Clapeyron equation:
ΔP = -3556.36 Pa
But the pressure change is said to lower the boiling point of water, only a negative pressure change will lower the boiling point.
ΔP = 3556.36 Pa
An energy transfer, with heat energy moving away from the equator
Answer:
vHe / vNe = 2.24
Explanation:
To obtain the velocity of an ideal gas you must use the formula:
v = √3RT / √M
Where R is gas constant (8.314 kgm²/s²molK); T is temperature and M is molar mass of the gas (4x10⁻³kg/mol for helium and 20,18x10⁻³ kg/mol for neon). Thus:
vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol
vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol
The ratio is:
vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol
vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol
<em>vHe / vNe = 2.24</em>
<em />
I hope it helps!
