Answer:12 mol
Explanation: both vessels are at the same temp and pressure (and the pressure is low and/or the temperature high).
6.7mol per 1.3L = 6.7/1.3 mol/L
so in 2.33L = 6.7*2.33/1.3 = 12 mol
Answer:
It is composed of 57.17% S and 42.83% C and has a molar mass of 448.70 g/mol. Determine the empirical and molecular formulas of “sulflower.”
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what is the molecular formula of the compound?
Empirical formula Molar mass (g/mol) Molecular formula
CHO 116.1
C8H16
Explanation:
Hope this helps
1,38×10²² = 0,138×10²³
0,138×10²³ ----- 1,5g
6,02×10²³ ------ X
X = (1.5×6,02×10²³)/0,138×10²³
X = 65,435 g/mol
It's ZINC (Zn)
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The rate of a reaction with this rate law would increase by a factor of 4 if NO concentration were doubled.
