(

)we need 3 equations
1. midpoint equation which is (

) when you have 2 points
2. distance formula which is D=

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height
so
x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(

)
midpoint=(

)
midpoint= (15,8)
point x=(15,8)
y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(

)
midpoint=(

)
midpoint=(13,4)
Y=(13,4)
legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D=

D=

D=

D=

D=

BC=

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D=

D=

D=

D=

D=

XY=

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=

and XY=

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D=

D=

D=

D=

D=

AD=

so we have
AD=

BC=
XY=

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(

) times 1/2 times

=
(

) times \sqrt{5} [/tex] =

=

=80

=252.982
X=(15,8)
Y=(13,4)
BC=

XY=

Area=80

square unit or 252.982 square units
It is B because u need enough for it to do it right
X= 9 1/4 or 9.25 in decimal form
2x^2 + 5x + 2 = 0
(x + 2)(2x + 1) = 0
x = -2 x = - 1/2
Letter C
Mid point of x:
{2-(-6)} : 2
8 : 2
4
mid point of y:
(5-3) : 2
2 : 2
1
so (4,1)