2 years ago

Integral of (sin(2x) + cos(2x)) dx=

1 answer:

3 0

$\displaystyle \int (\sin 2x + \cos 2x)~ dx\\\\=\displaystyle \int \sin 2x ~dx + \displaystyle \int \cos 2x ~ dx\\\\=-\dfrac{\cos 2x}2 + \dfrac{\sin 2x}2 +C\\\\=\dfrac{\sin 2x - \cos 2x}2+C$

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Answer:

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3 years ago

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ElenaW [278]

Answer:

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3 years ago

How do I find the endpoint of a segment when given the first endpoint (-6, 5) and the midpoint(-1.5, 1)?

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Graph: desmos.com/calculator/aze920ns2h

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