Answer:
There were 3 adults
Step-by-step explanation:
Step 1: Derive the first expression
a+c=10...equation 1
where;
a=number of adults
c=number of children
And total number of people=10
Step 2: Derive the second expression;
Total cost of tickets=(price per child ticket×number of children)+(price per adult ticket×number of adults)
where;
Total cost of tickets=$186.50
price per child ticket=$15.95
price per adult ticket=$24.95
number of children=c
number of adults=a
replacing;
(15.95×c)+(24.95×a)=186.5
24.95 a+15.95 c=186.5....equation 2
Step 3: Combine equation 1 and 2 and solve simultaneously
24.95 a+15.95 c=186.5
-
24.95(a+c=10)
(24.95 a-24.95 a)+(15.95 c-24.95 c)=186.5-(24.95×10)
-9 c=-63
c=-63/-9
c=7
replace the value for c in equation 1
a+c=10
a+7=10
a=10-7
a=3
There were 3 adults
<h3>
Answer: 8/17</h3>
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Explanation:
The rule is
If A+C = 90, then sin(A) = cos(C). We could also say cos(A) = sin(C).
I recommend drawing out the picture of what's going on. See below.
sin(A) = 8/17 has the opposite side 8 over hypotenuse 17.
cos(C) = 8/17 has 8 as the adjacent side now. The hypotenuse stays the same.
So that's why sin(A) = cos(C).
the answer is
In AKLM, the measure of ZM=90°
Answer:
The original deposited amount in the bank is $3500.
Step-by-step explanation:
Here. Let us assume the principal amount deposited in bank = $P
The rate of interest = 8%
Total Amount in the bank after time period = $4340
Time Period = 3 yrs
Now, SIMPLE INTEREST 
⇒ SI = 
or Interest = 0.24 P
Now, AMOUNT = PRINCIPAL + INTEREST
⇒$4340 = P + 0.24 P
or, 4340 = 1.24 P
⇒ P = 1340 / 1.24 = 3500
Hence, the deposited amount in the bank for the duration of 3 years and interest rate 8% is $3500
Answer:
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
Step-by-step explanation:
<u>Equivalent algebraic expressions</u> are those expressions which on simplification give the same resulting expression.
Two algebraic expressions are said to be <u>equivalent</u> if their values obtained by substituting any values of the variables are same.
Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.
Hence,
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.