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2 years ago

PLS HELP!!! FIRST ANSWER GETS BRAINLIEST!!!

Mathematics

1 answer:

olga55 [171]2 years ago

5 0

Answer:C

Step-by-step explanation:11m is the radius and to find the diameter u multiply 11 x 2 which is radius x 2 which = 22

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Find the equation of the line that passes through the points (3,-2) and (6,-8)

Karolina [17]

Answer:

$2x + y = 4$

Step-by-step explanation:

The two-point form of the equation of a line is:

$y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)$

We have:

x1 = 3

y1 = -2

x2 = 6

y2 = -8

Plug in all the values where they belong in the equation above.

$y - (-2) = \dfrac{-8 - (-2)}{6 - 3}(x - 3)$

Simplify.

$y + 2 = \dfrac{-6}{3}(x - 3)$

$y + 2 = -2(x - 3)$

$y + 2 = -2x + 6$

$2x + y = 4$

3 0

2 years ago

MATHEMATICS: A boy leaves home at 09:15 hours and arrives at 10:05 hours. If he travels nonstop at an average speed of 6kmh ,wha

love history [14]

Answer:

5 km.

Step-by-step explanation:

We have to calculate the distance if we apply the speed formula that would be the distance in a given time:

v = d / t

therefore, if we solve for distance it would be:

d = v * t

Now the speed is 6 km / h but the time must be calculated, it leaves at 9:15 and returns at 10:05, that is, there is no exact time but 50 minutes, one hour equals 60 minutes, therefore:

50 min * 1 h / 60 min = 0.833 h, that is, the child took 0.833 hours to get to school, now if we replace:

d = 6 * 0.8333

d = 5

In other words, the distance between the school and the house is 5 km.

5 0

2 years ago

Gordon has a round tablecloth with a radius of 4 feet. What is the tablecloth's diameter?<br> feet

lozanna [386]

Answer:

it's a round so

d=2r

d=8 feet

8 0

2 years ago

49÷369 explain answer

Afina-wow [57]

49 divided by 369 is 0.13279133 and 369 divided by 49 is 7.53061224

5 0

3 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

2 years ago