Brent estimates that the model's circumference is about 3 times the measure of the circle's diameter, with this, he can estimate the area.
<h3>What is a
circle? </h3>
A circle is the locus of a point, such that the distance from a fixed point (center) is always constant.
The circumference of a circle is given by:
Circumference = π * diameter
Brent estimates that the model's circumference is about 3 times the measure of the circle's diameter, with this, he can estimate the area.
Find out more on circle at: brainly.com/question/24375372
Answer:
Ok! When given points, to find the slope, you would use this equation: y2-y1/x2-x1. Let me demonstrate. In this set to find the slope with the coordinates (10,8) and (14,20), the y2 value is 20, and the y1 value is 8, and the x2 value is 14, and the y1 value is 10. So, your equation would look like this: (20-8)/(14-10), which simplifies to 12/4, or 3! So the slope is three, and that's how you do that when using an equation. OR, you could graph them, but that isn't too reliable so I do not recommend trying it, since you may not create the right slope.
Answer:
here u can look
Mark as brainlist
Step-by-step explanation:
X + y = 120(being alternate angle)
or,X=120-y
then
2x-y=120
or,2(120-y) - y= 120
240-2y-y=120
y=240-120
y= 120
again,
X=120-y
= 120-120
=0
hence,
X= 0
y= 120
Answer:
10 feet
Step-by-step explanation:
100/10=10
Answer:
a) 
b)
Step-by-step explanation:
We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point given and a slope from the equation. We will chose point-slope since we have a point and can find the slope.
Point slope:
a) 
in our new equation because it is perpendicular to it. This means we will need to change it into its negative reciprocal which is 
.
We will substitute and 
.
This simplifies to:
b) The equation y=3x+4 follows y=mx+b. For the perpendicular line, 
. We will need to change it into its negative reciprocal which is 
.
We will substitute and 
.
