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3 years ago

7

The tables show the cost for different numbers of song downloads.

2 answers:

iren [92.7K]3 years ago

8 0

Answer:

D

Step-by-step explanation:

its the right answer bc its proportional

ANEK [815]3 years ago

5 0

D it’s
proportional
that why

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18% of the cars in the parking lot are blue.If there are 150 cars in the parking lot,how many cars are blue

Ivanshal [37]

Answer:

Step-by-step explanation:

14

8 0

3 years ago

. What are the equation and slope of the line that is parallel to the y-axis and goes through the point (1,-2)?

Brrunno [24]

The answer:

x = 1

Explanation:

If the line is parallel to the y-axis it has no slope, so you would only write down the x-intercept.

8 0

3 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago

Engineers want to design brakes that will reduce stopping distances by 10%. How would this change the equation relating speed s,

AlekseyPX

For the answer to the question above, we will use this formula to solve this problem
<span>d = kv^2 </span>

<span>plugging in, </span>
<span>4.2 = k*10^2 </span>
<span>k = 0.042 </span>

<span>d = 0.042v^2 </span>

<span>the revoised equation will be </span>
<span>d = 0.9*0.042v^2 , i.e. </span>

<span>d = 0.0378v^2

I hope my answer helped you</span>

8 0

3 years ago

Andru [333]

I = PRT

14,300 = (700)(0.0725)(t)
14,300 = 50.75(t)
14300/50.75 = t
281.77 = t or t = 281.77

hope this helps :)

4 0

3 years ago