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UkoKoshka [18]
3 years ago
8

Combine like terms

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0

1. 7y

2. 28 + 14s

3. -2f - 4

4. 16 + 8d

5. 10 + 9r

6. -18+ 16s

7. -8q

8. 6h - 18

9. 12q - 2

10. 10d -27

sleet_krkn [62]3 years ago
3 0

Answer:

1.7y

2.-14s

3.-2f

4.23d

5.19r

6.-2s

7.-9q

8.24h

9.10q

10.23d

Step-by-step explanation:

I TRY MY BEST TO SOLVE IT

HOPE IT HELPS

CORRECT ME IF I AM WRONG

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Step-by-step explanation:

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3 years ago
The coordinates of points M,N, and P are ....
Rainbow [258]

Answer:

(-1, -1) Let me know if the explanation didn't make sense.  

Step-by-step explanation:

If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left.  This means M is only connected to N here and P is only connected to N.  So we want to find the slope of these two lines.

MN is easy since their y values are the same, the slope is 0.

NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.

So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0.  To find these lines  weuse point slope form  for those two points.  The formula for point slope form is y - y1 = m(x-x1)

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So now we want these two to intersect.  We just set them equal to each other.

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3 years ago
The output of a chemical process is continually monitored to ensure that the concentration remains within acceptable limits. Whe
marissa [1.9K]

Answer:

a)  0.31 = 31%

b) 0.03 = 3%

c) 0.36 = 36%

d) 2 times

Step-by-step explanation:

If F_X(x) is the cumulative distribution function of the random variable X, then by definition the probability P of the random variable is given by

P(X \leq x) = F_X(x)

If additionally the random variable is discrete (only has non-negative integers as outcomes as is the case in this problem) then

P(X=a)=F_X(a)-\lim_{x \to a^-}F_X(x)

a)

We are looking for P(X<2)

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b)

In this case we want P(X>3)

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c)

Now, we are interested in P(X=1)

P(X =1) =F_X(1)-\lim_{x \to 1^-}F_X(x)=0.53-0.17=0.36

d)

The expected number of times that the process is recalibrated during the week is the expected value of the probability distribution:

P(X=1)+2P(X=2)+...+nP(X=n)+...

But it is easy to see that P(X=n) = 0 if n is an integer >4

So, the expected value is

P(X=1)+2P(X=2)+3P(X=3)+4P(X=4)

We already have P(X=1) and P(X=2). Let's compute the rest

P(X =3) =F_X(3)-\lim_{x \to 3^-}F_X(x)=0.97-0.84=0.13

P(X =4) =F_X(4)-\lim_{x \to 4^-}F_X(x)=1-0.97=0.03

and the expected value is

0.36 + 2*0.53+3*0.13+4*0.03= 1.93 = 2 times rounding to the nearest integer.

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