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2 years ago

A 5’5 person weight 4.4kg. How many pounds is this

Mathematics

1 answer:

marshall27 [118]2 years ago

6 0

Answer:

9.70034

Step-by-step explanation:

1kg=2.20462 pounds, just do the math! I hope this helped.

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What’s the correct answer for this question?

scoray [572]

Answer: choice D 1/2

Step-by-step explanation:

Events A and B are independent if the equation P(A∩B) = P(A) · P(B) holds true.

1/6=1/3*p(A)

p(A)=1/2

4 0

3 years ago

Choose the measurement that is greater.<br> peck<br> bushel

daser333 [38]

Answer:

Bushel

Step-by-step explanation:

The Difference Between a Bushel and a Peck

Both are a dry volume measure of quarts. A bushel is equal to 32 quarts, while a peck is equal to 8 quarts, or a quarter of a bushel.

5 0

2 years ago

Read 2 more answers

The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch

DedPeter [7]

Answer:

The surface area is equal to $390\ in^{2}$

Step-by-step explanation:

The surface area of the triangular pyramid is equal to the area of its four triangular faces

In this problem

$SA=4[\frac{1}{2}(b)(h)]$

we have

$b=15\ in$

$h=13\ in$

substitute the values

$SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}$

4 0

2 years ago

Read 2 more answers

Visit the official Florida _____ page to find all the driving laws and information you need to know for the Class E knowledge ex

Nata [24]

Answer:

Where can I find specific information on Florida driving laws? Visit the official Florida driver's handbook page to find all of the driving laws and information you need to know for the Class E knowledge exam.

Step-by-step explanation:

7 0

2 years ago

Find the derivative.

Aleksandr [31]

Answer:

Using either method, we obtain: $t^\frac{3}{8}$

Step-by-step explanation:

a) By evaluating the integral:

$\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du$

The integral itself can be evaluated by writing the root and exponent of the variable u as: $\sqrt[8]{u^3} =u^{\frac{3}{8}$

Then, an antiderivative of this is: $\frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}$

which evaluated between the limits of integration gives:

$\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}$

and now the derivative of this expression with respect to "t" is:

$\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}$

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

$g(x)=\int\limits^x_a {f(t)} \, dt$

is continuous on [a,b], differentiable on (a,b) and $g'(x)=f(x)$

Since this this function $u^{\frac{3}{8}$ is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

$\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}$

5 0

2 years ago