Answer:
a. The allele for round seeds is dominant to the allele for wrinkled seeds.
Explanation:
Mendel found that when two pure breeding plants that differ from each other with respect to one genetic trait are crossed, all the progeny express the phenotype of one parent. The phenotype of the other parent is not expressed in the progeny. He concluded that the genetic trait that is expressed in the F1 generation is dominant over the other which is masked in this generation.
A cross between pure breeding plants for round seeds and the wrinkled seeds obtained all the round seeded progeny. This meant that the phenotype "round" was dominant over the phenotype "wrinkled". If the allele "R" gave round phenotype and the allele "r" imparted wrinkled phenotype, the allele "R" was dominant to the "r".
<span>The answer is cysteine. This is a half essential proteinogenic amino acid with the formulation of HO₂CCHCH₂SH. It is prearranged by the codons UGU and UGC. The thiol side chain in cysteine frequently partakes in enzymatic responses, as a nucleophile.</span>
the answer is it has a long half life
Answer:
2.glucose move into chamber B faster than fructose
Explanation:
- Facilitated diffusion: refers to the transport of hydrophilic molecules that are not able to freely cross the membrane. Channel protein and many carrier proteins are in charge of this <u>passive transport</u>. If uncharged molecules need to be carried <u>this process depends on concentration gradients</u> and molecules are transported from a higher concentration side to a lower concentration side. If ions need to be transported this process depends on an electrochemical gradient. The glucose is an example of a hydrophilic protein that gets into the cell by facilitated diffusion. Facilitated diffusion is a passive transport process because the cell does not need any energy to make it happen.
The exposed scenario is an example of facilitated diffusion, a process that occurs in favor of the concentration gradient, and which rate depends on the concentration of molecules in each side of the membrane, in this case, glucose and fructose, among other factors that might also influence the diffusion rate. So, as the concentration of glucose is higher in chamber A (80%), and lower in chamber B (20%), in comparison with fructose, the first one will diffuse faster than fructose. The difference in concentration between both chambers is sharper in glucose, so its transport is faster than the fructose transport, which will also diffuse but at a lower rate.
Answer: the beaks of the finches are adapted to the way the bird usually gets food. :) good luck!
