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3 years ago

Select each equation that the number 103 makes true.

Mathematics

1 answer:

kkurt [141]3 years ago

4 0

Answer:

None of those is right

But if you have to put something then try A and B

Step-by-step explanation:

Here's the right answer for each equation

A. 100

B. 1000

C. 1000

D. 10000

E. 100

So if the question was to select each equation that the number 100 makes true.

Then the answers would have been A and E

Hope this helps, have a beautiful day

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Last January, the average cost of a one-night stay at a hotel was $132.52. Since then, the hotel has changed ownership, and

Nikolay [14]

Answer:

$114.32

Step-by-step explanation:

Original Price: $132.52

increased: $34.65

Loyalty Club: -$57.80

Phone Fee: $4.95

You add all of them together, except for the Loyalty Club Fee. You subtract that fee by the total.

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3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

4 years ago

50 points!!!Adam recorded the number of flower blooms on each of his ten rose bushes. 9, 10, 4, 12, 15, 17, 18, 10, 12, 13If he

lyudmila [28]

Answer:

Step-by-step explanation:

9, 10, 4, 12, 15, 17, 18, 10, 12, 13

Putting the numbers from smallest to largest

4,9, 10, 10, 12 12, 13, 15, 17, 18,

The median is the middle number

There are 10 numbers

4,9, 10, 10, 12 12, 13, 15, 17, 18,

The middle number is between the 12's, so it is 12

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4 years ago

Read 2 more answers

Help me QUICK<br> Picture included of the problem

Klio2033 [76]

I think it would be a and f :)

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3 years ago

An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha

hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

$Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}$

Cross multiply

|AB|X Tan 15 =3000

|AB| = $\frac{3000}{Tan 15}$ =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

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3 years ago