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gizmo_the_mogwai [7]

3 years ago

6

Select each equation that the number 103 makes true.

1 answer:

kkurt [141]3 years ago

4 0

Answer:

None of those is right

But if you have to put something then try A and B

Step-by-step explanation:

Here's the right answer for each equation

A. 100

B. 1000

C. 1000

D. 10000

E. 100

So if the question was to select each equation that the number 100 makes true.

Then the answers would have been A and E

Hope this helps, have a beautiful day

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The angles of a triangle are 128 degrees 5x + 10 degrees + 9x degrees what is the value of x

olganol [36]

All the angles in a triangle equal 180 degrees so 128 + (5x+10) + 9x = 180

Group the like values to get 138 + 14x = 180

Subtract 138 from 180 to get 14x = 42

Divide 42 by 14 to get x = 3

Therefore x = 3

6 0

3 years ago

Cos X<br> Y<br> 12<br> X<br> 16<br> 20<br> Z<br> 4<br> A) 3/4<br> B) 4/3<br> C)3/5<br> D) 5/4

yanalaym [24]

Answer:

C.

$\cos X = \frac{12}{20} \\ = \frac{3}{5}$

5 0

3 years ago

Help a fella out Y'all. please n thank you

Virty [35]

Alrighty mate.

I reckon the answer as hmmm...I'd say<u><em> D</em></u>. All ya gotta do is just cover up the opposite variable and solve for the intercept yar lookin' for.

I hope I helped mate.

3 0

3 years ago

I need help...Idk what to do because this is all it gave me.

elixir [45]

Answer:

69

Step-by-step explanation:

A hexagon has 720 degrees in total. You add allthe numbers which is 513 degrees. Then you subtract them which is 207 degrees. Finally you divide 207 by 3 which is 69 :)

8 0

3 years ago

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

3 years ago