All categories

3 years ago

Read the photo and please answer!!

Mathematics

2 answers:

OverLord2011 [107]3 years ago

8 0

Answer:

It will be 3 + 3x= 45 because 3 is how much she already know and 3 with the x is how much she will learn. x=15 because 3 × 15 equals 45so that's how many weeks. pls make me brainliest thank you!:) btw the other person not right!!

Readme [11.4K]3 years ago

5 0

Answer:

Step-by-step explanation:

45 = 3x + 3 ⇒ <em>x = 14</em>

You might be interested in

!!!! PLS HELP I NEED THE WORK ILL DO WHATEVER!!!! brainlist<

AleksAgata [21]

What do you have to do in that problem?

4 0

3 years ago

Please help me out here

Liula [17]

Answer:

40*

Step-by-step explanation:

the whole line FC would measure 180* so then 180-50 for AGC then AGB is congruent to EGD so 180-50-90---> 130-90---> 40* so angleBGC is 40 degrees

6 0

2 years ago

Graph the description of each line A line has a slope of -3 and a y-intercept of 3.

Basile [38]

Answer:

The equation is y = -3 + 3

Step-by-step explanation:

It will go through (0,3) and it wil go up 3 right one.

5 0

2 years ago

Read 2 more answers

Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from

Lapatulllka [165]

<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$ </h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

$x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and y_3=8$

The area of a triangle is= $\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]$

= $|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|$

= $|-54|$ = 54 square units

The length of AC = $\sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}$

= $\sqrt{(2-12)^{2} +(1-8)^2}$

= $\sqrt{149}$ units

Let the perpendicular distance from B to AC be = x

According To Problem

$\frac{1}{2} \times x \times \sqrt{149} = 54$

⇔ $x =\frac{108}{\sqrt{149} }$ units

Therefore the perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$

5 0

3 years ago

C)PLEASE MAN PEOPLE ARE USING ME FOR POINTS

UNO [17]

The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.

<u>Interquartile Range: </u>

Given the Data -> First Quartile = 2, Third Quartile = 5

Interquartile Range = 5 - 2 = 3

<u>Range:</u> 8 - 1 = 7

<u>Variance: </u>

We start by determining the mean,

$\:1+\:2+\:3+\:3+\:3+\:5+\:8 / 7 = 3.57$

n = number of numbers in the set

Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.

$\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n-1},\\\\=> SS/n - 1\\\\=> 31.714/7 - 1\\=> 5.28571$

5.3

<u>Standard Deviation</u>

We take the square root of the variance,

$\sqrt{5.28571} = 2.29906$

2.3

If you are not familiar with variance and standard deviation, just leave it.

3 0

3 years ago

Read 2 more answers