Solve for y 20x + 5y = 30 y = 0 simplify
2 answers:
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Answer:
option b
1 , 16, 121 , 13456
Step-by-step explanation:
Given in the question a function, f(x) = (x - 5)²
initial value = 4
First iteration
f(x0) = f(4) = (4 - 5)² = (-1)² = 1
x1 = 1
Second iteration
f(x1) = f(1) = (1 - 5)² = (-4)² = 16
x2 = 16
Third iteration
f(x2) = f(16) = ( 16 - 5)² = (11)² = 121
x3 = 121
Fourth iteration
f(x3) = f(121) = (121 - 5)² = (116)² = 13456
x4 = 13456
Answer:
p ∈ [5 , 6)
Step-by-step explanation:
p + 6 ≥ 11
⇒ p ≥ 11 - 6
⇒ p ≥ 5
⇒ p ∈ [5 , +∞)
3p < 18
⇒ p < 18/3
⇒ p < 6
⇒ p ∈ (-∞ , 6)
Then
p the solution to both equations verify:
p ∈ (-∞ , 6) ∩ [5 , +∞)
Conclusion :
p ∈ [5 , 6)
