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3 years ago

Solve for y 20x + 5y = 30 y = 0 simplify

Mathematics

2 answers:

stepladder [879]3 years ago

5 0

It should be 25xy that is the correct answer i did this today

Cloud [144]3 years ago

4 0

Answer:

y=6−4x

Step-by-step explanation:

Subtract 20x from both sides of the equation then divide by 5. y=6−4x

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What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

Read 2 more answers

How do you get the answer to 10+12y=2y+40

stepladder [879]

Y = 3

Exp:

10 + 12y = 2y + 40
- 2y = - 2y

10 + 10y = 40
-10 -10

10y = 30
/ 10 / 10

y = 3

4 0

3 years ago

Help me

Komok [63]

Answer:

system of equations are

y=53x + 10, y=55x

Step-by-step explanation:

y=mx+b where x is the number of tickets purchased and y is the total cost.

We need to frame the equation for each option

Option 1: $53 for each ticket plus a shipping fee of $10

1 ticket cost = 53

So x tickets cost = 53x

shipping fee = $10 so b= 10

So equation becomes y=53x + 10

Option 2: $55 for each ticket and free shipping

1 ticket cost = 55

So x tickets cost = 55x

shipping fee =0 so b= 0

So equation becomes y=55x

5 0

2 years ago

A vending machine operator has determined that the number of candy bars sold per week by a certain machine is a random variable

docker41 [41]

Answer:

The answer is below

Step-by-step explanation:

Let Y represent the profit per day, and x represent the number of bar sold per day. Hence:

Y = 0.25x - 2

a) The mean is given as:

$\mu_y=E(Y)=E(0.25X-2) = 0.25E(X)-2\\\\But\ E(X)=mean\ of\ machine=125. Hence:\\\\E(Y)=0.25(125)-2=29.25\\\\E(Y)=\$29.25$

b) The standard deviation of y is:

$\sigma_y=var(0.25X-2)\\\\\sigma_y=0.25\sigma(X)\\\\but\ \sigma_X=7,hence:\\\\\sigma_y=0.25(7)=1.75\\\\\sigma_y=\$1.75$

6 0

3 years ago

Guided Practice

KATRIN_1 [288]

Answer:

i would think its C

Step-by-step explanation:

the other options dont make sense lol

hope this is correct and helps :)

5 0

3 years ago

Read 2 more answers