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frez [133]
2 years ago
5

A bag contains coins of rupees 2 Rupees 1 and 50 paise, in ratio of 1 is to 2 is to 4. if the total amount is rupees 72 find how

many 50 paise coins are there?
​
Mathematics
1 answer:
BabaBlast [244]2 years ago
4 0

Answer:

<u>Final </u><u>answer </u><u>-</u>

number \: of \: 50 \: paise \: coins \: in \: the \: bag = 4x \\ \dashrightarrow{4 \times 12 = 48 \: coins}

hope helpful :D

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katovenus [111]

Answer:

55/43

Step-by-step explanation:

(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43

6 0
2 years ago
Can someone please help me with numbers 23 and 24 it is easy
Dmitriy789 [7]

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8 0
3 years ago
Paloma has 3 jackets, 6 scarves, and 4 hats. What is the number of different outfits consisting of a jacket, a scarf, and a hat
Charra [1.4K]

Answer:

72

Step-by-step explanation:

We need to multiply all of them because there are 3 choices for jackets, 6 for scarves and so on.

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2 years ago
Im new to this app can someone help me please and thank u so much
GaryK [48]

Answer:

3\frac{1}{4}

Step-by-step explanation:

we have to  divide the given distance by 3.

Then we will be able to find the distance between markers.

Given distance is

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So, the distance between markers is-

\frac{\frac{39}{4}} {3} \\=\frac{39}{4} * \frac{1}{3} \\=\frac{13}{4}


So, the distance between marker is

\frac{13}{4}

Now, we have to convert this into mixed number.

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4 0
3 years ago
Sin0=12/37 find tan0
alexira [117]

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • We're provide - Sin θ = \frac{12}{37} which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = \tt{  \frac{p}{h}} ] . We're asked to find out tan θ ].

\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :

\large{ \tt{❊ \:  {h}^{2}  =  {p}^{2}  +  {b}^{2} }}

\large{ \tt{⇢ {p}^{2} +  {b}^{2}   =  {h}^{2} }}

\large{ \tt{⇢ \:  {b}^{2}  =  {h}^{2}  -  {p}^{2} }}

\large{ \tt{⇢ \:  {b}^{2} = {37}^{2} -  {12}^{2}   }}

\large{ \tt{⇢ \:  {b}^{2}  = 1369 - 144}}

\large{ \tt{ ⇢{b}^{2}  = 1225}}

\large{ \tt{⇢ \: b =  \sqrt{1225}}}

\large{ \tt{⇢ \: b = 35  \: \text {units}}}

  • Now , We know - Tan θ= \tt{ \frac{perpendicular}{base} }. Just plug the values :

\large{ \tt{➝ \: Tan  \: \theta =  \frac{p}{b}  = \boxed{ \tt{  \frac{12}{35} }}}}

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5 0
3 years ago
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