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NARA [144]
2 years ago
12

3(x + y) + 2x2 + (1 + y)?

Mathematics
2 answers:
stiks02 [169]2 years ago
6 0

Answer:

7x+4y+1

Don’t low if you wanted it simplified

irina [24]2 years ago
4 0

Answer:

3x + 4y + 5

Step-by-step explanation:

3(x + y) + 2 • 2 + (1 + y)

3x + 3y + 2 • 2 + (1 + y)

3x + 4y + 4 + 1

3x + 4y + 5

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How many terms in 9a+11p
Naddik [55]

Answer:

2 terms

Step-by-step explanation:

Terms are nothing but the mixtures of co-effecients and their variables..

Here, 9a is one term while 11p is the other

7 0
3 years ago
Read 2 more answers
Sean took 4 hours to travel from Town A to Town B at an
labwork [276]

Answer:

Tina's average speed  for the whole journey = 56 kmph

Step-by-step explanation:

Time taken by Sean to travel from Town A to Town B = 4 hours.

Average speed of Sean = 70 km/h

We have equation of motion, s = ut + 0.5 at²

Time, t = 4 hours.

Initial speed, u = 70 km/hr

Acceleration, a = 0 m/s²

Substituting

      s = ut + 0.5 at²

      s = 70 x 4 + 0.5 x 0 x  4²

       s = 280 km

Distance from Town A to Town B = 280 km

Tina took 1 hour more than Sean.

Time taken by Tina to travel from Town A to Town B = 4 +1 = 5 hours

We have equation of motion, s = ut + 0.5 at²

Time, t = 5 hours.

Displacement, s = 280 km

Acceleration, a = 0 m/s²

Substituting

      s = ut + 0.5 at²

      280 = u x 5 + 0.5 x 0 x  5²

       u = 56 km/hr

Tina's average speed  for the whole journey = 56 kmph

6 0
3 years ago
Ajar contains "x" black and "y" white balls. What is the probability that a random draw is black?
Levart [38]

Answer:

Step-by-step explanation:

favorable events=x

total number of events=x+y

P=(favorable events)/(total number of events)=x/(x+y)

8 0
3 years ago
Read 2 more answers
For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?​
konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1

After solving we get value of y=-1

Now putting in eq(1) to get value of x

x+2y=0\\x+2(-1)=0\\x-2=0\\x=2

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3

So, After solve the equations we get value of k=3

4 0
3 years ago
Ann cuts her brownie into six equal parts and eats three pieces. Chris cuts his brownie into ten equal parts and eats four piece
Trava [24]

Answer:

no

Step-by-step explanation:

Ann ate 3/6, or 1/2 (50%) of hers.

Chris ate 4/10, or 2/5 (40%) of his.

Chris has more left.

5 0
3 years ago
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