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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
The ratio between them is approximately , therefore the correct answer is A.
Step-by-step explanation:
In order to calculate the ratio of the diameter of the Sun to the diameter of the Earth we will first represent the Earth's diameter as a scientific notation, to do this we will add one to the power of ten for every time the comma walks to the left until there's only one number to the left. This is done to make the division easier,
The ratio is given by the Sun's diameter divided by the Earth's, as shown below:
The ratio between them is approximately , therefore the correct answer is A.