HELLPPP
1 answer:
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Given:
Mean, μ = 22
Standard deviation, σ = 7
Let's answer the following questions.
a. Given:
Sample size, n = 25
Let's find the probability that the sample mean is between 21.5 and 22.5.
We have:
Therefore, the probability that sample mean is between 21.5 and 22.5 is 0.279
b. Given:
n = 25
Let's find the probability that the sample mean is between 21 and 22 minutes.
We have:
[tex]\begin{gathered} P(21Using the standard normal table, we have:[tex]\begin{gathered} P(-0.714286Therefore, the probability that sample mean is between 21 and 22 is 0.2625c. Given:
n = 144
Let's find the probability the sample mean is between 21.5 and 22.5
[tex]\begin{gathered} P(21.5Therefore, the probability that sample mean is between 21.5 and 22.5 given a sample of 144 is 0.6086d. Given:
Sample size in a = 25
Sample size in c = 144
The sample size in c is greater than the sample size in a so the standard error of the mean in (c) should be less than the standard error in (a).
As the standard error values become more concentrated
Answer:
Therefore the rate at which water level is dropping is in per minute.
Step-by-step explanation:
Given that,
The diameter of cylindrical bucket = 12 in.
Depth is increasing at the rate of = 4.0 in per minutes.
i.e
is depth of the bucket.
The volume of the bucket is V =
Differentiating with respect yo t,
Putting
The rate of volume change of the bucket = The rate of volume change of the aquarium .
Given that,The aquarium measures 24 in × 36 in × 18 in.
When the water pumped out from the aquarium, the depth of the aquarium only changed.
Consider h be height of the aquarium.
The volume of the aquarium is V= ( 24× 36 ×h)
V= 24× 36 ×h
Differentiating with respect to t
Putting
Therefore the rate at which water level is dropping is in per minute.
Answer:
Step-by-step explanation:
<em>m∠D</em> = 90° - 51° = <em>39°</em>
sin E = ⇒ DE = DF × sin E
<em>DE</em> = 18 sin51° ≈ <em>14.0 ft.</em>
cos E = ⇒ EF = DF × cos E
<em>EF</em> = 18 × cos51° ≈ <em>11.3 ft.</em>
