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olasank [31]
2 years ago
7

WILL MARK BRAINLIEST FOR CORRECT ANSWER.

Mathematics
2 answers:
kiruha [24]2 years ago
7 0

Short Answer

It's A

Solution

A

2/3 x - 2 = 1/3 x                             Subtract 2/3x from both sides

2/3x - 2/3x - 2 = 1/3x - 2/3 x        Combine like terms

- 2 = - 1/3 x                                    Multiply both sides by - 3

- 2  * - 3 = 3 * - 1/3 x

- 6 = - x                                          Multiply by -1

x = 6

B

B looks like the same thing, but the 2 is a plus 2. When you solve for x you go through exactly the same steps. Your answer becomes - 6

C

C adds 2/3 x to both sides. The result is x = - 2

D same as C only x = 2

Phoenix [80]2 years ago
3 0

I would simplify each equation and then plug in 6 for x.

A.) \frac{2}{3}x-2= \frac{1}{3} x  Subtract 2/3x on both sides

\frac{2}{3}x-2- \frac{2}{3}x= \frac{1}{3}x-\frac{2}{3}x

-2=-\frac{1}{3}x  Now you plug in 6

-2=-\frac{1}{3} (6)

-2 = -\frac{6}{3}

-2 = -2


x = 6 is the solution for choice A

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or

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Step-by-step explanation:

Let's do synthetic division.

We are dividing by x+2, so -2 will be on the outside. Like this:

-2 |         1          13          32         20

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The remainder is 0, so (x+2) is indeed a factor of x^3+13x^2+32x+20.

The other factor we found by doing this is (x^2+11x+10).

You can find more factors by factoring x^2+11x+10.

Two numbers that multiply to be 10 and add to be 11 is 10 and 1 so the factored form of x^2+11x+10 is (x+10)(x+1).

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