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galina1969 [7]
3 years ago
9

Can somebody please answer this for me will give Brainliest

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0
1.) -2/3
2.) (0, 2)
3.) (0, 3)
I don’t know how to answer 4 and 5 sorry
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A bag of marbles contsins 6 red, 8 green and 5 blue. what is the probability of picking a green
vekshin1
6+8+5=19
Probability= 8/19=0.42= 42% of picking green.
3 0
3 years ago
Click on the graphic to select the figure that would make the following a reflection in line k
Roman55 [17]

I remember answering the same question, but you didn't attach any photos. But I remember that the answer is the first one.

I hope I helped. Stay safe and God bless!

- Eli <3

6 0
4 years ago
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
The length of a rectangle is three times its width. if the area of the rectangle is 300 yd2 , find its perimeter.
Svetradugi [14.3K]
Let, width = x
Length = 3x

It is given that, 3x * x = 300
3x² = 300
x² = 300 / 3
x = √100
x = 10
& 3x = 3(10) = 30

Perimeter = 2(l + w)
P = 2(10 + 30)
P = 2(40) = 80

In short, Your Answer would be 80 Yards

Hope this helps!
4 0
3 years ago
Given cot A = 5/6 and that angle A is in Quadrant I, find the exact value of csc A in
Lerok [7]

Answer: well search It up 1/10

Step-by-step explanation:

8 0
3 years ago
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