thanks 4 the points lolllll
Answer:
Yes
Step-by-step explanation:
First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.
It has mean μ= np = 30×0.56=16.8
standard deviation s = √npq
sqrt(30×0.56×(1-0.56)) = 2.71
So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.
1.00 would be your answer because 95 rounded up is 100. So, 0.95 is closest to 1.00
Answer:
units
Step-by-step explanation:
The zero (0) is in the units place. unit = 1
Answer:
0.6666666666etc but you have to round it to 67 because it is closer to 67
Step-by-step explanation:
