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babunello [35]
3 years ago
10

Given: a//b c//d e//f, m<7=24, and m<20 = 80 what is m<1

Mathematics
1 answer:
Anna11 [10]3 years ago
3 0

Answer:

m∠1 = 100

Step-by-step explanation:

m∠2 = 80

m∠1 = 180 - 80 = 100

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Multiplying Polynomials Multiple Choice<br> Need to know what goes in blanks and final answer
maksim [4K]

Answer:

6x² - 19x + 10

Step-by-step explanation:

Given

(3x - 2)(2x - 5)

Each term in the second factor is multiplied by each term in the first factor, that is

3x(2x - 5) - 2(2x - 5) ← distribute both parenthesis

= 6x² - 15x - 4x + 10 ← collect like terms

= 6x² - 19x + 10

8 0
3 years ago
3 3/4 x = 1 1/4<br> 7/5 x = 7/15<br><br> x has to be the same in both equations.
madam [21]

Answer:

x = 1/3

Step-by-step explanation:

3 3/4x = 1 1/4

15/4x = 5/4

x = 5/4 * 4/15

x = 5/15 which reduces to 1/3

7/5x = 7/15

x = 7/15 * 5/7

x = 7/21 which reduces to 1/3

7 0
3 years ago
Solve the equation for y.<br> 1 5. *x+y=4
Olegator [25]

You simply need to subtract x from both sides:

x+y=4 \iff x+y-x=4-x \iff y=4-x

In fact solving an equation for a variable means to isolate that variable on one side of the equation, and moving all remaining terms on the other side.

In this case, we solved the equation for y, because we wrote it as y=\ldots

7 0
3 years ago
What is the value of the number 3 in the the number 12,532.628
Vera_Pavlovna [14]

What is the value of the number 3 in the the number 12,532.628

Solution

Here we need to use the place chart. I have attached the place value chart.

According to the place chart 3 is in tens place.

Therefore, the value of the number 3 in the number 12,532.628 is   3 x 10 = 30.


The answer is 30.

8 0
3 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
3 years ago
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