The decomposition of so3 to so2 gas and o2 gas can be described in the balanced chemical equation:
2so3(g) = 2 so2 (g) + 02(g).
so assuming a complete reaction, the ratio of so2 gas to total products is 2/3 while that of 02 is 1/3.
Subtracting water's water vapor pressure, 760-40 mm hG = 720 mm Hg.
then the products partial pressures are
so2 = 2/3 * (720) = 480 mm Hg.
o2 = 720-480 = 240 mm Hg.
Answer is: temperature of helium is -296,95°C.
The temperature T<span> in degrees Celsius (°C) is equal to the temperature </span>T in Kelvin (K) minus 273,15: T(°C) = T(K) - 273.15.
T(He) = 4,2 K.
T(He) = 4,2 K - 273,15.
T(He) = -268,95°C.
The Celsius scale was based on 0°C for the freezing point of water and 100°C for the boiling point of water at 1 atm<span> pressure.</span>
it's either A. or C. because
