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3 years ago

Vectors are arrows that tell us two things about force...WEIGHT and DIRECTION

Chemistry

2 answers:

lorasvet [3.4K]3 years ago

6 0

False, from what i know vectors tell us about direction and magnitude. not weight and direction

Dvinal [7]3 years ago

5 0

It’s false because vectors doesn’t tell us two things about force weight and direction

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True or False? pH can only be between 1 and 14.TrueFalse

Alika [10]

Answer: The sentence given is false.

Explanation:

The question requires us to determine if the sentence given by the question ("pH can only be between 1 and 14") is true or false.

The pH value is matematically defined as:

$pH=-log\lbrack H^+\rbrack$

where [H+] is the concentration of H+ ions in solution.

If the concentration of H+ is too high, such as in an acid battery, the pH of a solution can reach 0. However, its value cannot be negative. Therefore, we can say that the pH scale ranges from 0 (very acidic medium) to 14 (very alkaline medium).

Considering the sentence given, we can say that it is false.

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1 year ago

3. What should you do after an earthquake when you are in a building?

balu736 [363]

Answer:

3. You should walk fast in moving out.

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5. Do not run

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3 years ago

Read 2 more answers

Which formula represents hydrofluoric acid?<br> HFO<br> H2F<br> HFO 4<br> HF

natulia [17]

Answer:

it's HF

Explanation:

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4 years ago

Read 2 more answers

How many atoms of oxygen are represented in 2Fe(NO3)2? ( My answer: C) Correct?

astra-53 [7]

How many atoms of oxygen are represented in 2Fe(NO3)2?

Answer: 12

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4 years ago

Some SO2 and O2 are mixed together in a flask at 1100 K in such a way ,that at the instant of mixing, their partial pressures ar

kakasveta [241]

Answer:

The answer is " $\bold{0.525\ \ atm^{-1}}$ "

Explanation:

Given equation:

$2SO_2(g) + O_2(g) \leftrightharpoons 2SO_3(g)$

Given value:

$\Delta rH =-198.2 \ \ \frac{KJ}{mol}$

$Kp=1100 \ K$

$\Delta x = 2-(2+1)\\\\$

$= 2-(2+1)\\\\= 2-(3)\\\\= -1$

$\left\begin{array}{cccc}I\ (atm)&1&0.5&0\\C\ (atm)&2x&-x&2x\\E\ (atm) &1-2x&0.5-x&2x\end{array}\right$

calculating the total pressure on equilibrium= $(1-2x)+(0.5-x)+2x \ atm\\\\$

$= 1-2x+0.5-x+2x\\\\= 1+0.5-x\\\\=1.5-x\\$

$\therefore \\\\\to 1.50-x= 1.35 \\\\\to 1.50-1.35= x\\\\\to 0.15= x\\\\ \to x= 0.15\\\\$

calculating the pressure in $So_2$ :

$= (1-2 \times 0.15)$

$= 1-0.30 \\\\ =0.70 \ atm$

calculating the pressure in $O_2$ :

$= (0.5- 0.15)\\\\= 0.35 \ atm \\$

calculating the pressure in $So_3$ :

$= (2 \times 0.15)\\\\= (.30) \ atm \\\\$

Calculating the Kp at 1100 K:

$= \frac{(Pressure(So_3))^2}{(Pressure(So_2))^2 \times Pressure(O_2)}\\\\= \frac{0.30^2}{0.70^2 \times 0.35}\\\\= \frac{0.30 \times 0.30 }{0.70\times 0.70 \times 0.35}\\\\= \frac{0.09 }{0.49\times 0.35} \\\\= \frac{0.09 }{0.1715} \\\\= 0.5247 \ \ or \ \ 0.525 \ \ atm^{-1} \\\\$

4 0

3 years ago