The bigger the atomic radius the easier it is to oxidise the atom. Remember that an atom is oxidized by the loss of an electron.
Explanation:
The bigger the atomic radius the further away the valence electron are from the attractive force of the atomic nucleus. This means that the energy required to remove an electron from the valence shell is easier compared to an atom with a smaller atomic radius. This is because you need to overcome the attractive force of the nucleus on the electron for you to oxidize the atom.
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For more on oxidation energy check out;
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Anesthetic in dentistry consists of a mixture of dinitrogen oxide (N₂O) and oxygen gas (O₂), which is administered through an inhaler over the nose. Total pressure of the mixture (
) is sum of partial pressure of N₂O (
) and partial pressure of O₂, (
).

=370 mmHg
So,
= (740-370) mmHg= 370 mmHg=370 torr
Hence, partial pressure of N₂O is 370 torr.
As, 1mmHg= 1 torr.
Weak base: [OH⁻] = √Kb.C
pKb = 4.2

c = concentration
MM Amphetamine (C9H13N) = 135.21 g/mol
c = 215 mg/L = (0.215 g : 135,21 g/mol) / L = 0.00159 mol/L = 1.59 x 10⁻³ mol/L
![\tt [OH^-]=\sqrt{10^{-4.2}\times 1.59\times 10^{-3}}=3.17\times 10^{-4}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7B10%5E%7B-4.2%7D%5Ctimes%201.59%5Ctimes%2010%5E%7B-3%7D%7D%3D3.17%5Ctimes%2010%5E%7B-4%7D)
pOH = 4 - log 3.17
pH = 14 - (4 - log 3.17)
pH = 10 + log 3.17 = 10.50
Answer:
The answer to your question is 43.9 g of NaCl
Explanation:
Data
Grams of NaCl = ?
Volume = 0.75 L
Molarity = 1 M
Number of moles = ?
Formula

Solve for number of moles
Number of moles = Molarity x volume
Substitution
Number of moles = 1 x 0.75
= 0.75
Molecular weight of NaCl = 23 + 35.5 = 58.5
Calculate the grams of NaCl using proportions
58.5 g of NaCl ---------------- 1 mol
x ---------------- 0.75 moles
x = (0.75 x 58.5) / 1
x = 43.9 g of NaCl
<span>Cl</span>₂<span> + 2NaBr → 2NaCl + Br</span>₂
The mole ratio of Cl₂ : Br₂ is 1 : 1