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ahrayia [7]
2 years ago
11

Please Help..., This Is Due Tomorrow I need 385 X 445 step by step

Mathematics
2 answers:
pentagon [3]2 years ago
6 0

Answer:

32725

Step-by-step explanation:

             385

           <u> x445</u>      

            1925

          15400

        <u>+15400</u>

         32725

Hope this helps :)

Rainbow [258]2 years ago
4 0
The answer is 171, 325 just use a calculator
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Which shows the image of ΔRST after the rotation (x, y) → (y, –x)?
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Answer: I need help pls

Step-by-step explanation:

4 0
3 years ago
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2 divided by 3460 explanation please
LUCKY_DIMON [66]
<span>2/3460              Original Mathematical Expression.

1/1730                Divide numerator and denominator by 2.

This equals . . .

</span><span>0.00057803468

(I just plugged 1/1730 into calculator)

Final Answer: 1/1730 or </span><span>0.00057803468</span>
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3 years ago
Round to the nearest tenth. 8.54
Katarina [22]
The answer would be 8.5. 8.54 rounds down to 8.54. 
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3 years ago
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Triangle ABC is isosceles with AB=CB. Circle M is inscribed in Triangle ABC such that it is tangent at points D, E, and F. If th
Ierofanga [76]

Answer:

The answer is "12 inches".

Step-by-step explanation:

Please find the image file of the graph.

We know AE = CF \ and \ EB = FB so because the triangle is isosceles.

EB = 2x, FB = 2x,\ and \ CF = x when AE is called by x.

We know that AE = AD = x since E and D are tangent points to a circle.

They have CD = CF = x since D and F are tangent points only to circle.

Thus, if the perimeter is 32, the following is the result:

\to AE + EB + BF + FC + CD + DA = 32\\\\\to x + 2x + 2x + x + x + x = 32\\\\\to 8x = 32\\\\\to x = 4

Therefore the length of BC = BF + FC = 2x + x = 3x = 12\  inches

8 0
3 years ago
Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.
Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0
3 years ago
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