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3 years ago

Simplify: −3−2[4−1].

Mathematics

1 answer:

jasenka [17]3 years ago

8 0

-3-2 (4-1) simplified is -9

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A(3,4),B(5,8),C(7,8) are the vertices of ABC, prove that the line passing through the mid point of AB and AC is parallel to BC

Ede4ka [16]

<h2>Explanation:</h2><h2></h2>

$The \ midpoint \ formula \ of \ the \ line \ segment \\ that \ joins \ the \ two \ points \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ is \\ given \ by \ the \ following \ Midpoint \ Formula:\\ \\ Midpoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

Let's name the mid point of $AB$ as $c$

Let's name the mid point of $AC$ as $p$

Then:

$c=(\frac{3+5}{2},\frac{4+8}{2}) \\ \\ c=(\frac{8}{2},\frac{12}{2}) \\ \\ c=(4,6) \\ \\ \\ p=(\frac{3+7}{2},\frac{4+8}{2}) \\ \\ p=(\frac{10}{2},\frac{12}{2}) \\ \\ p=(5,6)$

So the slope of the line that passes through $c \ and \ p$ is:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m_{cp}=\frac{6-6}{5-4}=0$

And the slope for BC is:

$m_{BC}=\frac{8-8}{7-5}=0$

As you can see, both slopes are zero, so these are horizontal lines.

5 0

4 years ago

Dana has ⅘ cup of ice cream. How many ⅛ cup servings are in ⅘ cup of ice cream?

mario62 [17]

Answer:

A 6.4

Step-by-step explanation:

(4/5)/(1/8) this is the answer

8 0

4 years ago

Read 2 more answers

Solve for n , 5/16 = n/80

kow [346]

5/16=n/80

Cross multiply

16n=400

n=400/16

n=25

6 0

3 years ago

Read 2 more answers

Help solve both of these questions

Effectus [21]

Let's solve for a.
p
x
=
x
3
−
4
x
2
+
a
Step 1: Flip the equation.
x
3
−
4
x
2
+
a
=
p
x
Step 2: Add -x^3 to both sides.
x
3
−
4
x
2
+
a
+
−
x
3
=
p
x
+
−
x
3
−
4
x
2
+
a
=
−
x
3
+
p
x
Step 3: Add 4x^2 to both sides.
−
4
x
2
+
a
+
4
x
2
=
−
x
3
+
p
x
+
4
x
2
a
=
−
x
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p
x
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4
x
2

Answer:
a
=
−
x
3
+
p
x
+
4
x
2

3 0

3 years ago

Lucy has 4 more than 1/3 the number of pairs of socks as her sister. Lucy has at most 9 pairs of socks. How many pairs of socks

Volgvan

Answer: at most 15 pairs of socks

Step-by-step explanation:

Let the number of pair of socks of her sister be $x$ , and let the number of pairs Lucy has be $y$ .