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Dahasolnce [82]

3 years ago

7

3x=12-2y write in standard form

1 answer:

klio [65]3 years ago

6 0

Standard form is y = mx + b.

So,

3x = 12 - 2y
+ 2y + 2y

3x + 2y = 12
-3x - 3x

2y = -3x + 12
--- ---- ----
2 2 2

y = (-3/2)x + 6

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Can u answer this please?

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2 years ago

Solve the following linear equation for x x. 5 x − 2 + x = 9 + 3 x + 10 5x−2+x=9+3x+10

marta [7]

The answer is 6. Please mark BRAINLIEST!! :D

6 0

2 years ago

-112/3 x (-4 1/5) =?

TEA [102]

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3 0

2 years ago

What is -2 1/3 - (-5)=

Archy [21]

Answer:

$\frac{8}{3}$

Step-by-step explanation:

$- 2 \frac{1}{3} - ( - 5)$

convert mixed fraction into improper fraction.

$- \frac{7}{3} + ( - 5)$

calculate the sum of the fraction:

$\frac{8}{3}$

6 0

2 years ago

I answered it but I just need someone to answer just to make sure mine are right

Artemon [7]

<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

<u>Given</u>:

$m\angle Z = 138^{\circ}$

<em><u>Note the following:</u></em>

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

$m\angle 1 = 60^{\circ}$ (an angle in an equilateral triangle equals 60 degrees)

Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Learn more here:

brainly.com/question/2944195

5 0

2 years ago