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lutik1710 [3]
3 years ago
13

Plsssssssssssssssssssssss help me plsssssssssssssssssssssss please answer both it’s 1234 on both as well

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

Step-by-step explanation:

The exponent of 10³ is 3. To multiply a number by 10³, move the decimal point two places to the right:

42.12 × 10³ = 42120.

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Use the graph below to write the equation of the function
Ksivusya [100]

Answer:

c

Step-by-step explanation:

gefhhfeyjhtwgi15287

8 0
3 years ago
Need urgent help in mathematics!! Will mark brainliest!!!!
Nataly [62]

₇P₅ is a permutation. you can find this setting in the statistics menu of your scientific calculator (i think).

If you don't have a scientific calculator, you can use the following formula:

nPr = \frac{n!}{(n - r)!}

₇P₅  = \frac{7!}{(7 - 5)!}

     = \frac{7}{2!}

     = \frac{7 * 6 * 5 * 4 * 3 * 2!}{2!}

     = 7 * 6 * 5 * 4 * 3

    = 2520

Answer: C

3 0
3 years ago
Read 2 more answers
What is 0.5 repeating as a fraction in simplest form
Solnce55 [7]

Answer:

5/9

Step-by-step explanation:

Start be letting x = 0.555...

Our original equation is:

x = 0.555...

There is only one digit repeating, the 5, so we multiply both sides of that equation by 10 and write it above the original equation.

10x = 5.555...

   x = 0.555...

Now we subtract the second equation from the first equation as written above.

9x = 5

Divide both sides by 9.

x = 5/9

0.555... = 5/9

6 0
3 years ago
Box of 15 gadgets is known to contain 5 defective gadgets if 4 gadgets are drawn at random what is the probability of finding no
baherus [9]

To solve this problem, we make use of the Binomial Probability equation which is mathematically expressed as:

P = [n! / r! (n – r)!] p^r * q^(n – r)

where,

n = the total number of gadgets = 4

r = number of samples = 1 and 2 (since not more than 2)

p = probability of success of getting a defective gadget

q = probability of failure = 1 – p

 

Calculating for p:

p = 5 / 15 = 0.33

So,

q = 1 – 0.33 = 0.67

 

Calculating for P when r = 1:

P (r = 1) = [4! / 1! 3!] 0.33^1 * 0.67^3

P (r = 1) = 0.3970

 

 

Calculating for P when r = 2:

P (r = 2) = [4! / 2! 2!] 0.33^2 * 0.67^2

P (r = 2) = 0.2933

 

Therefore the total probability of not getting more than 2 defective gadgets is:

P = 0.3970 + 0.2933

P = 0.6903

 

Hence there is a 0.6903 chance or 69.03% probability of not getting more than 2 defective gadgets.

5 0
3 years ago
PLEASEE<br> Solve<br> x=6<br> 4x +y =20
Tanya [424]

Answer: y = -4

Step-by-step explanation:

4 (6) + y = 20

24 + y = 20

-24 -24

y = -4

8 0
2 years ago
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