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Hatshy [7]
3 years ago
15

A container of gas is held at a constant pressure. Which of these would cause both the volume of the gas and the average kinetic

energy of its molecules to increase?
A
increasing the number of gas molecules inside of the container
B
decreasing the number of gas molecules inside of the container
С
increasing the Kelvin temperature of the gas
D
decreasing the Kelvin temperature of the gas
Physics
2 answers:
Sloan [31]3 years ago
7 0
The correct answer is letter B
Nadusha1986 [10]3 years ago
7 0
The right answer is B
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Explanation:

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Scorpion4ik [409]

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Explanation:

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3 0
3 years ago
Which form of Kepler’s third law can you use to relate the period T and radius r of a planet in our solar system as long as the
ser-zykov [4K]

T2=r In the form of Kepler's law that can use to relate the period T and radius of the planet in our solar systems

<u>Explanation:</u>

<u>Kepler's third law:</u>

  • Kepler's third law states that For all planets, the square of the orbital

     period (T) of a planet is proportional to the cube of the average orbital    radius (R).

  • In simple words T (square) is proportional to the R(cube) T²2 ∝1 R³3
  • T2 / R3 = constant = 4π ² /GM

      where G = 6.67 x 10-11 N-m2 /kg2

        M = mass of the foci body

8 0
4 years ago
A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The
Goshia [24]

Answer:

0.629\ \text{rad/s}^2 counterclockwise

9.98\ \text{s}

Explanation:

r_1 = Small drive wheel radius = 2.2 cm

\alpha_1 = Angular acceleration of the small drive wheel = 8\ \text{rad/s}^2

r_2 = Radius of pottery wheel = 28 cm

\alpha_2 = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2

The angular acceleration of the pottery wheel is 0.629\ \text{rad/s}^2.

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}

t = Time taken

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}

The time it takes the pottery wheel to reach the required speed is 9.98\ \text{s}

4 0
3 years ago
Un prisma rectangular de cobre, de base igual a 36 centímetros cuadrados y una altura de 10 cm se sumerge hasta la mitad por med
butalik [34]

La respuesta correcta es 180 centímetros cúbicos o 180 cm^{3}

Explicación:

El primer paso para saber cuanto alcohol desaloja el prisma es calcular el volumen total del prisma. El volumen se puede encontrar usando la formula V (Volumen) = B (base) x h (altura). El proceso se muestra a continuación:

V  = B x h

V = 36 cm^{2} x 10 cm

V= 360 cm^{3}

Finalmente, el volumen total del prisma debe dividirse en 2 considerando que solo la mitad del prisma fue sumergida y esta mitad equivale al volumen del alcohol desplazado.

360 cm^{3} ÷ 2 = 180 cm^{3}  

5 0
3 years ago
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