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3 years ago

What do civic heroes contribute to their society?

Physics

1 answer:

azamat3 years ago

4 0

the quest for civic virtue

Explanation:

improving schools, the society....to help educators like yourself, the bill of rights institute has written a New classroom-friendly curriculum called Heroes and Villains....

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An electric model train is accelerated at a rate of 8 m/s^2 by a 12 N force? What is the

jok3333 [9.3K]

Answer:

m = 1.5 kg

Explanation:

Data:

Aceleration (a) = 8 m/s²
Force (F) = 12 N
Mass (m) = ?

Use formula:

$\boxed{m = \frac{F}{a}}$

Replace in the formula:

$\boxed{m = \frac{12N}{8\frac{m}{s^{2}}}}$

Equate the newtons:

$\boxed{m = \frac{12kg*\frac{m}{s^{2}}}{8\frac{m}{s^{2}}}}$

Simplify m/s²:

$\boxed{m = \frac{12kg}{8}}$

It divides:

$\boxed{m =1.5kg}$

What is the mass of the train?

The mass of the train is <u>1.5 kilograms.</u>

4 0

3 years ago

The frequency of the harmonics following a fairly simple pattern, as described in the text. If the frequency of the fundamental

zalisa [80]

Answer:

f2 = 140 Hz

Explanation:

let fundamental frequency is f1 = 70.0 Hz

formula for finding the higher frequency when fundamental frequency is known

fn = n f1 (where f1 is fundamental frequency and n = 1,2,3,4,5...........)

for the second frequency n=2

f2 = 2 × 70.0 Hz

f2 = 140 Hz

6 0

4 years ago

A pilot performs an evasive maneuver by diving vertically at 270. If he can withstand an acceleration of 9.0 's without blacking

mamaluj [8]

Answer:

The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

Explanation:

Given that,

Velocity = 270 m/s

Acceleration = 9.0g s

We need to calculate the altitude

Using formula of centripetal acceleration

$a_{c}=\dfrac{v^2}{r}$

$r=\dfrac{v^2}{a_{c}}$

Where, v = velocity

r = altitude

a = acceleration

Put the value into the formula

$r=\dfrac{270^2}{9.0\times9.8}$

$r=826.53\ m$

Hence, The pilot must be began at an altitude of 826.53 m to avoid crash into the sea.

6 0

3 years ago

HELP IM IN A EXAM!!!

natali 33 [55]

Answer:

Species A and C

Explanation: none

8 0

3 years ago

Read 2 more answers

A 2.0 kg block, initially moving at 10.0 m/s, slides 50.0 m across a sheet of ice beforecoming to rest. What is the magnitude of

inna [77]

Answer:

The magnitude of the average frictional force on the block is 2 N.

Explanation:

Given that.

Mass of the block, m = 2 kg

Initial velocity of the block, u = 10 m/s

Distance, d = 50 m

Finally, it stops, v = 0

Let a is the acceleration of the block. It can be calculated using third equation of motion. It can be given by :

$v^2-u^2=2ad$

$-u^2=2ad$

$a=\dfrac{-u^2}{2d}\\\\a=\dfrac{-(10\ m/s)^2}{2\times 50\ m}\\\\a=-1\ m/s^2$

The frictional force on the block is given by the formula as :

F = ma

$F=2\ kg\times (-1)\ m/s^2\\\\F=-2\ N$

|F| = 2 N

So, the magnitude of the average frictional force on the block is 2 N. Hence, this is the required solution.

8 0

4 years ago