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Naddik [55]
3 years ago
8

What are chlorofluorocarbons and what impact do they have on the atmosphere?

Physics
1 answer:
Sladkaya [172]3 years ago
8 0

Explanation :

Chlorofluorocarbons are abbreviated as CFC. It contains only carbon, fluorine, and chlorine. Initially, CFC is used as refrigerants.

Impact of chlorofluorocarbons on the atmosphere are :

(1) It damages the earth's ozone layer. So, it was banned in 1996.

(2) It also contributes to global warming.  

(3) They have lived in atmosphere of about 20 to 100 years.

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which of the following helps to explain why you can lift heavy objects more easily when they are in water
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Buoyancy from water. Buoyancy is an upward force on an object immersed in a fluid (i.e., a liquid or a gas), enabling it to float or at least to appear lighter.

3 0
3 years ago
WHICH ROLLER COASTER CART HAS THE LEAST POTENTIAL ENERGY DUE TO GRAVITY?
DIA [1.3K]

Answer:

C. Car A

Explanation:

if the answer is: which roller coaster car has the greatest potential energy due to gravity brainly

6 0
3 years ago
A submerged submarine alters its _____ to rise or fall in the water.
Dima020 [189]
Are there any answer choices?
Submarines use <span>buoyancy by filling ballast tanks up with water. When they are filled with water, they are more dense than the surrounding water, so they are able to sink. If they want to rise, they fill these tanks up with air so that the density is less than the water it surrounds. 
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3 0
3 years ago
Read 2 more answers
The blue mass is currently 4 meters away from the red mass.
umka21 [38]

Answer:

its a!

Explanation:

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6 0
3 years ago
My Notes Ask Your Teacher 6. Six blocks with different masses, m, each start from rest at the top of smooth, frictionless inclin
Tresset [83]

Answer:

Kf > Ka = Kb > Kc > Kd > Ke

Explanation:

We can apply

E₀ = E₁

where

E₀: Mechanical energy at the beginning of the motion (top of the incline)

E₁: Mechanical energy at the end (bottom of the incline)

then

K₀ + U₀ = K₁ + U₁

If v₀ = 0  ⇒  K₀

and  h₁ = 0   ⇒    U₁ = 0

we get

U₀ = K₁    

U₀ = m*g*h₀ = K₁

we apply the same equation in each case

a) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

b) U₀ = K₁ = m*g*h₀ = 70 Kg*9.81 m/s²*8m = 5493.60 J

c) U₀ = K₁ = m*g*h₀ = 35 Kg*9.81 m/s²*4m = 1373.40 J

d) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*16m = 1098.72 J

e) U₀ = K₁ = m*g*h₀ = 7 Kg*9.81 m/s²*4m = 274.68 J

f) U₀ = K₁ = m*g*h₀ = 105 Kg*9.81 m/s²*6m = 6180.30 J

finally, we can say that

Kf > Ka = Kb > Kc > Kd > Ke

8 0
3 years ago
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