Two workers pull horizontally on a heavy box, but one pulls twice as hard as the other. The larger pull is directed at 25.0 ∘ we
st of north, and the resultant of these two pulls is 590.0 N directly northward.Use vector components to find the magnitude of each of these pulls. Assume that the smaller pull has a component directed to the north and Use vector components to find the direction of the smaller pull. Assume that the smaller pull has a component directed to the north.
<span>The smaller pull is "F" and the larger pull is "2F". The east-west components of F and 2F cancel. The north components add to 460 N. 2Fcos25 + FcosΘ = 460 2Fsin25 - FsinΘ = 0 where Θ is measured cw from +y axis (east of north) In the second equation, F cancels, leaving 2sin25 = sinΘ = 0.845 → Θ = 58º East of North Using the first equation, then, 2Fcos25 + Fcos58 = 1.813F + 0.534F = 2.347F = 460 F = 196 N 2F = 392 N</span>
An example of a weak base is ammonia. It does not contain hydroxide ions, but it reacts with water to produce ammonium ions and hydroxide ions. The position of equilibrium varies from base to base when a weak base reacts with water. The further to the left it is, the weaker the base.
