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Whitepunk [10]
3 years ago
5

What do electric forces between charges depend on

Physics
1 answer:
denis23 [38]3 years ago
7 0

Answer:

On the magnitude of the charges, on their separation and on the sign of the charges

Explanation:

The magnitude of the electric force between two charges is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

From the formula, we see that the magnitude of the force depends on the following factors:

- magnitude of the two charges

- separation between the charges

Moreover, the direction of the force depends on the sign of the two charges. In fact:

- if the two charges have same sign, the force is repulsive

- if the two charges have opposite signs, the force is attractive

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A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface. (a) What type of char
DiKsa [7]

Answer with Explanation:

a. Option d is true.

a negatively charged plane parallel to the end faces of the cylinder

b. Radius of cylinder, r=0.66m

Magnitude of electric field, E=300 N/C

We have to find the net flux through the closed surface.

Net electric flux,\phi=-2 EA=-2E(\pi r^2)

\phi=-2\times 300\times (3.14\times (0.66)^2)

\phi=-820.67 Nm^2/C

c.

Net charge,Q=\epsilon_0\times \phi

Where

\epsilon_0=8.85\times 10^{-12}

Q=-820.67\times 8.85\times 10^{-12}

Q=-7.26\times 10^{-9} C

Q=-7.26nC

Where 1nC=10^{-9}C

7 0
3 years ago
Which one of the following statements indicates the result of Kepler's astronomical calculations?
garri49 [273]
The correct answer for the question that is being presented above is this one: "<span>c. Planets orbit in elliptical patterns; a planet's orbit covers equal areas in equal amounts of time; planets' orbits are shorter or longer depending on their distance from the Sun."</span>

Here are the following choices:
a. Planets orbit in elliptical patterns; the bigger the planet, the more gravitational pull; a planet's gravitational pull is stronger or weaker depending on its distance from the Sun.

b. A planet's orbit covers equal distances in equal amounts of time; the speed of a planet's orbit depends on its distance from the Sun; the bigger the planet, the slower it moves.

c. Planets orbit in elliptical patterns; a planet's orbit covers equal areas in equal amounts of time; planets' orbits are shorter or longer depending on their distance from the Sun.
5 0
3 years ago
The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g o
satela [25.4K]

Answer:

Q = 50.25 [J]

Explanation:

To solve this problem we must use the following equation that relates the temperature change with the mass and with the specific heat.

Q = m*Cp*(DT)

where:

Q = energy in form of heat [J]

m = mass = 5 [g] = 0.005 [kg]

Cp = specific heat = 1005 [J/kg*°C]

DT = temperature change = 10 [°C]

Now replacing:

Q = 0.005*1005*10

Q = 50.25 [J]

4 0
4 years ago
Which term describes an area of low density in a longitudinal wave?
LiRa [457]

Answer:

Explanation:

Low density is an area of rarefaction.

6 0
3 years ago
Read 2 more answers
The colors of the stars in the sky range from red to blue. Assuming that the color indicates the frequency at which the star rad
Crazy boy [7]

Answer:

a) 4458K b) 5048K, c) 6166K, d) 5573K

Explanation:

The temperature of the stars and many very hot objects can be estimated using the Wien displacement law

    \lambda_{max} T = 2,898 10⁻³ [m K]

    T = 2,898 10⁻³ / \lambda_{max}

a) indicate that the wavelength is

    Lam = 650 nm (1 m / 109 nm) = 650 10⁻⁹ m

    Lam = 6.50 10⁻⁷ m

    T = 2,898 10⁻³ / 6.50 10⁻⁷

    T = 4,458 10³ K

    T = 4458K

b) lam = 570 nm = 5.70 10⁻⁷ m

    T = 2,898 10⁻³ / 5.70 10⁻⁷

    T = 5084K

c) lam = 470 nm = 4.70 10⁻⁷ m

    T = 2,898 10⁻³ / 4.7 10⁻⁷

    T = 6166K

d) lam = 520 nm = 5.20 10⁻⁷ m

    T = 2,898 10⁻³ / 5.20 10⁻⁷

    T = 5573K

5 0
4 years ago
Read 2 more answers
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