Answer:
<em>Johnny had </em><em>5</em><em> items and Bobby had </em><em>13</em><em> items.</em>
Step-by-step explanation:
Let us assume that Johnny has x items and Bobby has y items in their list.
Bobby had 3 more than twice as many items on it than Johnny. So,
----------1
Johnny asked for 8 fewer items than bobby. So,
-----------2
Putting the value of x from equation 2 in equation 1, we get
Putting the value of y in equation 2,
So, Johnny had 5 items and Bobby had 13 items.
D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30
0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters
d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes
its y2-y1 over x2-x1 and you plug in 4 and 8 for x1 and x2 and then 61 and 108 for y1and y2
D.) The mean will increase
The mean is all the numbers added together than divided by the amount of numbers there, so if you do this: 4 + 6 = 10 + 16 = 26 + 15 = 41/5 = 8.2
4 + 6 = 10 + 16 = 26 + 15 = 41 + 23 = 64/6 = 10.66666666666
As you can see it increased! Hope this helped! Pls give brainiest if you can
