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ki77a [65]
3 years ago
15

Evaluate the expression for a = 27, b = 26, c = 27, d = 23: a+b-c-d

Mathematics
1 answer:
artcher [175]3 years ago
5 0

For this case we have the following expression:

a + b-c-d

We must evaluate the expression when:

a = 27\\b = 26\\c = 27\\d = 23

Substituting the values we have:

a + b-c-d = 27 + 26-27-23

Equal signs are added and the same signs are placed.

a + b-c-d = + 53-50

Different signs are subtracted and the sign of the major is placed:

a + b-c-d = 53

Finally we have to:

a + b-c-d = 53

Answer:a + b-c-d = 53

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Please help me with this question.
Rufina [12.5K]

 

m∠AOC = 108°

m∠AOC = 3m∠AOB

⇒m∠AOB = (m∠AOC) / 3 = 108 / 3 = 36°



3 0
3 years ago
I you were flipping a nickel a dime and a quarter how many possible outcomes are possible for getting heads or tails
zhuklara [117]
3/6 possible out comes for heads and tails
8 0
3 years ago
let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
3 years ago
The monomial of the 2nd degree with a coeficcient of 3
uranmaximum [27]
I assume it is the last one, 3n^2, because the degree is the exponent, which is two and the three is the coefficient, which is next to the variable, plus it is a monomial, so there is only one term, eliminating the first two, the third one is just reversed. Therefore, the answer should be the last one. Hope this helps. :)
4 0
2 years ago
Read 2 more answers
Let’s assume the 147 freshman maintained a 65% attendance rate during the first 4 week of school. If our next 4 week goal for at
shutvik [7]

Answer:

  • 12 students  

Step-by-step explanation:

If 65% equals 147

Then to maintain 70% there is a need for 5% more

<u>Which equals</u>

  • 5*147/65 ≈ 12 students
4 0
3 years ago
Read 2 more answers
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