Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]:

Derivative Property [Addition/Subtraction]:

Derivative Rule [Basic Power Rule]:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Integration
Integration Rule [Reverse Power Rule]:

Integration Property [Multiplied Constant]:

Integration Methods: U-Substitution and U-Solve
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify given.</em>
<em />
<u>Step 2: Integrate Pt. 1</u>
<em>Identify variables for u-substitution/u-solve</em>.
- Set <em>u</em>:

- [<em>u</em>] Differentiate [Derivative Rules and Properties]:

- [<em>du</em>] Rewrite [U-Solve]:

<u>Step 3: Integrate Pt. 2</u>
- [Integral] Apply U-Solve:

- [Integrand] Simplify:

- [Integral] Rewrite [Integration Property - Multiplied Constant]:

- [Integral] Apply Integration Rule [Reverse Power Rule]:

- [<em>u</em>] Back-substitute:

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.
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Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Answer:32
Step-by-step explanation: (2+3x)= 98 then solve
Answer:
sum(2^(n+1), for n=1 to 6)
Step-by-step explanation:
To answer this question, you need to know two things:
- what is an expression for the n-th term
- how many terms are there
__
The series shown is a geometric series with first term 4 and common ratio 8/4 = 2. The generic form of the n-th term is ...
an = a1×r^(n-1) . . . . first term a1, common ratio r
You can use this form directly in your summation expression, or you can simplify it a bit.
an = 4×2^(n-1) = (2^2)(2^(n-1)) = 2^(n-1+2)
an = 2^(n+1)
__
The value 128 is 2^7, so n+1 = 7, or n=6 for that term
Your summation expression could be ...

_____
<em>Additional comment</em>
The n-th term can also be written as 2×2^n.
We simply multiply to solve this problem.
6000*3/5
18000/5
3600
Thus, 3600 is our answer.
Y=4x because 20/5 equals 4