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ki77a [65]
3 years ago
15

Evaluate the expression for a = 27, b = 26, c = 27, d = 23: a+b-c-d

Mathematics
1 answer:
artcher [175]3 years ago
5 0

For this case we have the following expression:

a + b-c-d

We must evaluate the expression when:

a = 27\\b = 26\\c = 27\\d = 23

Substituting the values we have:

a + b-c-d = 27 + 26-27-23

Equal signs are added and the same signs are placed.

a + b-c-d = + 53-50

Different signs are subtracted and the sign of the major is placed:

a + b-c-d = 53

Finally we have to:

a + b-c-d = 53

Answer:a + b-c-d = 53

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Draw a number line and mark all described points on it.
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Answer:

<em>See attached</em>

<u>Numbers are either negative or greater tan 5:</u>

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7 0
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A factory worker can make 14 products in 45 minutes.what is the workers unit rate
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Candy. Someone hands you a box of a dozen chocolate-covered candies, telling you that half are vanilla creams and the other half
BaLLatris [955]

Answer:

a) P=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but it is still possible that there are 6 of each taste.

c) The probability of picking 4 vainilla in a row, if there are half of each taste, is P=0.030.

This is a very improbable case, so if this happens we would have reasons to think that there are more than half vainilla candies in the box.

Step-by-step explanation:

We can model this problem with the variable x: number of picked vainilla in a row, following a hypergeometric distribution:

P(x=k)=\dfrac{\binom{K}{k}\cdot \binom{N-K}{n-k}}{\binom{N}{n}}

being:

N is the population size (12 candies),

K is the number of success states in the population (6 vainilla candies),

n is the number of draws (3 in point a, 4 in point c),

k is the number of observed successes (3 in point a, 4 in point c),

a) We can calculate this as:

P(x=3)=\dfrac{\binom{6}{3}\cdot \binom{12-6}{3-3}}{\binom{12}{3}}=\dfrac{\binom{6}{3}\cdot \binom{6}{0}}{\binom{12}{3}}=\dfrac{20\cdot 1}{220}=0.091

b) If there are half of each taste, picking 3 vainilla in a row has a rather improbable chance (9%), but is possible.

c) In the case k=4, we have:

P(x=3)=\dfrac{\binom{6}{4}\cdot \binom{6}{0}}{\binom{12}{4}}=\dfrac{15\cdot 1}{495}=0.030

This is a very improbable case, so we would have reasons to think that there are more than half vainilla candies in the box.

4 0
3 years ago
Very counfused on this
Lilit [14]

Answer:

Step 1: Fill three gallon jug

Step 2: Pour the water from the three gallon to the five gallon jug

Step 3: Refill three gallon jug

Step 4: Pour three gallon jug into five jug until full (this leaves one gallon in the three gallon tank.

Step 5: Dump out the water in the five gallon jug

Step 6: Pour the 1 gallon of water into the five gallon jug

Step 7: Refill the 3 gallon jug

Step 8: Pour the 3 gallons into the five gallon jug (3 + 1 = 4)

Step 9: Place jug on scale.

Hope this helps!

4 0
3 years ago
392512329 in word form
kramer
Three hundred ninety two million five hundred twelve thousand three hundred twenty nine
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3 years ago
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