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ki77a [65]
3 years ago
15

Evaluate the expression for a = 27, b = 26, c = 27, d = 23: a+b-c-d

Mathematics
1 answer:
artcher [175]3 years ago
5 0

For this case we have the following expression:

a + b-c-d

We must evaluate the expression when:

a = 27\\b = 26\\c = 27\\d = 23

Substituting the values we have:

a + b-c-d = 27 + 26-27-23

Equal signs are added and the same signs are placed.

a + b-c-d = + 53-50

Different signs are subtracted and the sign of the major is placed:

a + b-c-d = 53

Finally we have to:

a + b-c-d = 53

Answer:a + b-c-d = 53

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A company has budgeted 5 1/4 hours to complete a project, with 1/3 of the time spent on research. How much time does the company
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Given that a company budgeted 5 1/4 hours to complete a project, determine how much time they spent on research if they spent 1/3 of the total budget.

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4 years ago
At the beginning of each year for 14 years, Sherry Kardell invested $400 that earns 10% annually. What is the future value of Sh
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Hmm if I'm not mistaken, is just an "ordinary" annuity, thus 

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]
\\\\\\

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &400\\
r=rate\to 10\%\to \frac{10}{100}\to &0.1\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, so once}
\end{array}\to &1\\

t=years\to &14
\end{cases}
\\\\\\
A=400\left[ \cfrac{\left( 1+\frac{0.1}{1} \right)^{1\cdot 14}-1}{\frac{0.1}{1}} \right]

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3 years ago
Read 2 more answers
How many strings of eight english letters are there
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