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ki77a [65]
3 years ago
15

Evaluate the expression for a = 27, b = 26, c = 27, d = 23: a+b-c-d

Mathematics
1 answer:
artcher [175]3 years ago
5 0

For this case we have the following expression:

a + b-c-d

We must evaluate the expression when:

a = 27\\b = 26\\c = 27\\d = 23

Substituting the values we have:

a + b-c-d = 27 + 26-27-23

Equal signs are added and the same signs are placed.

a + b-c-d = + 53-50

Different signs are subtracted and the sign of the major is placed:

a + b-c-d = 53

Finally we have to:

a + b-c-d = 53

Answer:a + b-c-d = 53

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Help evaluating the indefinite integral
Dafna11 [192]

Answer:

\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

General Formulas and Concepts:
<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (cu)' = cu'

Derivative Property [Addition/Subtraction]:
\displaystyle (u + v)' = u' + v'
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:
\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:
\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution/u-solve</em>.

  1. Set <em>u</em>:
    \displaystyle u = 4 - x^2
  2. [<em>u</em>] Differentiate [Derivative Rules and Properties]:
    \displaystyle du = -2x \ dx
  3. [<em>du</em>] Rewrite [U-Solve]:
    \displaystyle dx = \frac{-1}{2x} \ du

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Apply U-Solve:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du
  2. [Integrand] Simplify:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du
  3. [Integral] Rewrite [Integration Property - Multiplied Constant]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du
  4. [Integral] Apply Integration Rule [Reverse Power Rule]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C
  5. [<em>u</em>] Back-substitute:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
2 years ago
Help me! :( will appreciate any type of help
KengaRu [80]

Answer:32

Step-by-step explanation: (2+3x)= 98 then solve

8 0
3 years ago
Please help i dont know how to solve
den301095 [7]

Answer:

  sum(2^(n+1), for n=1 to 6)

Step-by-step explanation:

To answer this question, you need to know two things:

  • what is an expression for the n-th term
  • how many terms are there

__

The series shown is a geometric series with first term 4 and common ratio 8/4 = 2. The generic form of the n-th term is ...

  an = a1×r^(n-1) . . . . first term a1, common ratio r

You can use this form directly in your summation expression, or you can simplify it a bit.

  an = 4×2^(n-1) = (2^2)(2^(n-1)) = 2^(n-1+2)

  an = 2^(n+1)

__

The value 128 is 2^7, so n+1 = 7, or n=6 for that term

Your summation expression could be ...

  \displaystyle\sum_{n=1}^6{2^{n+1}}

_____

<em>Additional comment</em>

The n-th term can also be written as 2×2^n.

3 0
2 years ago
Show the equation what is 3/5 of 6000
andrey2020 [161]
We simply multiply to solve this problem.

6000*3/5

18000/5

3600

Thus, 3600 is our answer.
5 0
3 years ago
Which equation represents the relationship shown in the table?
Mila [183]
Y=4x because 20/5 equals 4
5 0
3 years ago
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