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3 years ago

6

When solving an absolute value inequality, the fact of whether it is a "greater than/greater than or equal to" as opposed to "le

ss than/less than or equal to" will change the way you solve the problem, depending on which sign it is.
True
False

1 answer:

Alex73 [517]3 years ago

7 0

It is true hopes this helps you

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Write an equation in slope-intercept form for the following line:<br><br> (-14,1) and (13,-2)

alex41 [277]

Answer:

$\large \boxed{y = - \frac{1}{9} x - \frac{5}{9} }$

Step-by-step explanation:

In order to find an equation of a line with two given ordered pairs. We have to find a slope first which we can do by using the formula below.

$\large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }$

m-term is defined as slope in y = mx+b form which is slope-intercept form.

Now we substitute these ordered pairs (x, y) in the formula.

$\large{m = \frac{1 - ( - 2)}{ -14 - 13} } \\ \large{m = \frac{1 + 2}{ - 27} } \\ \large{m = \frac{3}{ - 27} = - \frac{1}{9} }$

After we calculate for slope, we substitute m-value in slope-intercept form. The slope-intercept form is

$\large \boxed{y = mx + b}$

We already know m-value as we substitute it.

$\large{y = - \frac{1}{9} x + b}$

We are not done yet because we need to find the b-term which is our y-intercept. (Note that m-term is slope while b-term is y-intercept)

We can find the y-intercept by substituting either (-14,1) or (13,-2) in the equation. I will be using (13,-2) to substitute in the equation.

$\large{y = - \frac{1}{9} x + b} \\ \large{ - 2 = - \frac{1}{9} (13) + b} \\ \large{ - 2 = - \frac{13}{9} + b} \\ \large{ - 2 + \frac{13}{9} = b} \\ \large{ - \frac{5}{9} = b}$

Finally, we know b-value. Then we substitute it in our equation.

$\large{y = - \frac{1}{9} x + b} \\ \large{y = - \frac{1}{9} x - \frac{5}{9} }$

4 0

3 years ago

there are 70 students in the school band. 40% of them are sixth graders, 20 % are seventh graders, and the rest are eight grader

zheka24 [161]

Answer:

28 are 6th

14 and 7th

40% are 8th

Step-by-step explanation:

4 0

3 years ago

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Find all values of x in the interval [0,2π] that satisfy the equation sin2x=cosx. enter your answers as a list of numbers separa

yuradex [85]

$\sin(2x) = \cos(x) \\ 2 \sin(x) \cos(x) = \cos(x) \\ \cos(x) (2 \sin(x) - 1) = 0$
so
$\cos(x) = 0 > > > x = \frac{\pi}{2} + k\pi \\ \sin(x) = \frac{1}{2} > > > x = \frac{\pi}{6} + 2k\pi \\ or \: x = \frac{5\pi}{6} + 2k\pi$
$x = \frac{\pi}{2} or \frac{3\pi}{2} \\ x = \frac{\pi}{6} or \frac{5\pi}{6}$

6 0

3 years ago

Part b evaluate each expression if b = 3 5 b + 9 + 8B + 22 + 8 + 4

MrRissso [65]

Answer: 80

Step-by-step explanation: multiple b(3) with everything its next to, then add it all up

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2 years ago

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Find y when x=10 if y=8 when x=20

Gelneren [198K]

Answer:

16

Step-by-step explanation:

10=8

20=y

10*y = 8*20

10y= 160

y=16

3 0

3 years ago