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PilotLPTM [1.2K]
3 years ago
15

How do you find percent composition?

Chemistry
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

vdsfdvdsfdsf

Explanation:

https://newsengin.zendesk.com/hc/vew/community/posts/360056216292-%D9%85%D9%88%D9%82%D8%B9-%D8%A7%D9%84%D9%86%D9%88%D8%B1-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D8%A7%D9%84%D8%AB%D8%A7%D9%85%D9%86%D8%A9-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-%D9%82%D9%8A%D8%A7%D9%85%D8%A9-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9

https://newsengin.zendesk.com/hc/pst/community/posts/360056216252-Serial-TV-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-7-%D8%A7%D9%84%D8%B3%D8%A7%D8%A8%D8%B9%D8%A9-%D8%A7%D9%88%D9%86%D9%84%D8%A7%D9%8A%D9%86-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-7-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-HD

https://newsengin.zendesk.com/hc/vew/community/posts/360056216292-%D9%85%D9%88%D9%82%D8%B9-%D8%A7%D9%84%D9%86%D9%88%D8%B1-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D8%A7%D9%84%D8%AB%D8%A7%D9%85%D9%86%D8%A9-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-%D9%82%D9%8A%D8%A7%D9%85%D8%A9-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9

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Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
sergiy2304 [10]
The balanced chemical reaction is:

<span>3N2H4(l)→4NH3(g)+N2(g)
</span>
The amounts given for the N2H4 reactant will be the starting point for our calculations.

2.6mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 3.47 mol NH3

4.05mol N2H4 ( 4 mol NH3 / 3 mol N2H4 ) = 5.4 mol NH3

63.8g N2H4  <span>( 4 mol NH3 / 3 mol N2H4 ) = 85.07 mol NH3</span>
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