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iragen [17]
2 years ago
5

Consider the elements carbon, C and silicon, Si.

Chemistry
1 answer:
Aneli [31]2 years ago
3 0

Answer:

and

Explanation:

All the carbon group atoms, having four valence electrons, form covalent bonds with nonmetal atoms; carbon and silicon cannot lose or gain electrons to form free ions, whereas germanium, tin, and lead do form metallic ions but only with two positive charges

the similarities is that Both carbon and silicon commonly form compounds, easily sharing electrons with other elements. Carbon will make multiple bonds with other carbon molecules by forming single, double and triple covalent bonds. ... Carbon and silicon are often combined, with carbon serving as silicon's backbone.

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Gold is alloyed (mixed) with other metals to increase its hardness in making jewelry.
KiRa [710]

Answer:

A) 54.04%

B) 13-karat

Explanation:

A) From the problem we have

<em>1)</em> Mg + Ms = 9.40 g

<em>2)</em> Vg + Vs = 0.675 cm³

Where M stands for mass, V stands for volume, and g and s stand for gold and silver respectively.

We can rewrite the first equation using the density values:

<em>3)</em> Vg * 19.3 g/cm³ + Vs * 10.5 g/cm³ = 9.40

So now we have<em> a system of two equations</em> (2 and 3) <em>with two unknowns</em>:

We <u>express Vg in terms of Vs</u>:

  • Vg + Vs = 0.675 cm³
  • Vg = 0.675 - Vs

We <u>replace the value of Vg in equation 3</u>:

  • Vg * 19.3 + Vs * 10.5 = 9.40
  • (0.675-Vs) * 19.3 + Vs * 10.5 = 9.40
  • 13.0275 - 19.3Vs + 10.5Vs = 9.40
  • -8.8 Vs + 13.0275 = 9.40
  • <u>Vs = 0.412 cm³</u>

Now we <u>calculate Vg</u>:

  • Vg + Vs = 0.675 cm³
  • Vg + 0.412 cm³ = 0.675 cm³
  • Vg = 0.263 cm³

We <u>calculate Mg from Vg</u>:

  • 0.263 cm³ * 19.3 g/cm³ = 5.08 g

We calculate the mass percentage of gold:

  • 5.08 / 9.40 * 100% = 54.04%

B)

We multiply 24 by the percentage fraction:

  • 24 * 54.04/100 = 12.97-karat ≅ 13-karat
4 0
3 years ago
Would you like Brainliest?
lubasha [3.4K]

Answer:

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Explanation:

6 0
2 years ago
Read 2 more answers
What is the total number of grams of h2o produced when 22 grams of propane undergoes complete combustion?
SSSSS [86.1K]
The combustion reaction of propane would be expressed as:

C3H8 + 5O2 = 3CO2 + 4H2O

To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:

moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O

Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
5 0
3 years ago
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PIT_PIT [208]

i believe it would be B '' tetrahedral compound ''

6 0
3 years ago
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IUPAC NAME FOR<br><br> [Fe(H2O)6](NO3)3
sdas [7]

Explanation:

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