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Natalija [7]
3 years ago
11

The initial temperature of 150 g of ethanol was 22 C. What will be the final temperature of the ethanol if 3240 J was needed to

raise the temperature of the ethanol
Physics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

<h3>30.405°C</h3>

Explanation:

Using the formula for heart capacity;

Q = mcΔt

m is the mass = 150g = 0.15kg

initial temperature = 22°C

Quantity of heat = 3240J = 3.24kJ

specific heat capacity of ethanol = 2.57 [kJ/kg K]

Substitute and get the final temperature

3.240 = 0.15(2.57)(T - 22)

3.240 = 0.3855(T-22)

3.240/0.3855 = T - 22

8.405 = T - 22

T = 22+8.405

T = 30.405°C

Hence the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol is 30.405°C

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Answer:

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3 years ago
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laila [671]

Answer:

2 seconds

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A uniform meter rule with a mass of 200g is suspended at zero mark pivotes at 22.0cm mark. calculate the mass of the rule.
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Answer:

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Explanation:

Given;

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pivot of the uniform meter rule = 22 cm

Total length of meter rule = 100 cm

0                          22cm                                  100cm

-------------------------Δ------------------------------------

↓                                                                       ↓

200g                                                                 m₂  

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m₂ =  (200 g)(22 cm)  / (78 cm)

m₂ = 56.41 g  

Therefore,  the mass of the rule is 56.41 g                                            

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