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Natalija [7]
3 years ago
11

The initial temperature of 150 g of ethanol was 22 C. What will be the final temperature of the ethanol if 3240 J was needed to

raise the temperature of the ethanol
Physics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

<h3>30.405°C</h3>

Explanation:

Using the formula for heart capacity;

Q = mcΔt

m is the mass = 150g = 0.15kg

initial temperature = 22°C

Quantity of heat = 3240J = 3.24kJ

specific heat capacity of ethanol = 2.57 [kJ/kg K]

Substitute and get the final temperature

3.240 = 0.15(2.57)(T - 22)

3.240 = 0.3855(T-22)

3.240/0.3855 = T - 22

8.405 = T - 22

T = 22+8.405

T = 30.405°C

Hence the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol is 30.405°C

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If a particle undergoes shm with amplitude 0.21 m, what is the total distance it travels in one period?
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3 years ago
A child of mass 25 kg is skating fast, +10 m/s, and tries to get revenge by colliding with the 60 kg adult who is sitting still.
tankabanditka [31]

Answer: -4.4 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

p_{o}=p_{f} (1)

Where:

p_{o}=m_{1}V_{o}+m_{2}U_{o} (2)

p_{f}=m_{1}V_{f}+m_{2}U_{f} (3)

m_{1}=25 kg is the mass of the child

V_{o}=10 m/s is the initial velocity of the child

m_{2}=60 kg is the mass of the adult

U_{o}=0 m/s is the initial velocity of the adult (it is sitting still)

V_{f} is the final velocity of the child

U_{f}=6 m/s is the final velocity of the adult

Substituting (2) and (3) in (1):

m_{1}V_{o}+m_{2}U_{o}=m_{1}V_{f}+m_{2}U_{f} (4)

Isolating V_{f}:

V_{f}=\frac{m_{1}V_{o}-m_{2}U_{f}}{m_{1}} (5)

V_{f}=\frac{(25 kg)(10 m/s)-(60 kg)(6 m/s)}{25 kg} (6)

Finally:

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4 0
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Sodium sulfide formula is Na₂S.
Na is a group 1 element, it has one valence electron therefore it is ready to give that valence electron and form an ionic bond. Once it gives out the electron it becomes a positive ion - Na⁺
sulfur is a group 6 element, has 6 electrons its outer shell and needs to gain 2 more electrons to become stable. Once it gains 2 electrons it becomes a negative ion - S²⁻.
Since Na only gives out 1 electron, S²⁻ ion needs to take in 2 electrons, therefore forms an ionic compound with 2 Na⁺ ions.
decomposition of Na₂S is as follows;
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8 0
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Read 2 more answers
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