The answer would be 2.63. Your welcome. This has been changed to the correct answer.
Answer:
The average recoil force on the gun during that 0.40 s burst is 45 N.
Explanation:
Mass of each bullet, m = 7.5 g = 0.0075 kg
Speed of the bullet, v = 300 m/s
Time, t = 0.4 s
The change in momentum of an object is equal to impulse delivered. So,

For 8 shot burst, average recoil force on the gun is :

So, the average recoil force on the gun during that 0.40 s burst is 45 N.
Answer:
Yes
Explanation:
In a third-class lever, the effort force lies between the resistance force and the fulcrum. Some kinds of garden tools are examples of third-class levers. When you use a shovel, for example, you hold one end steady to act as the fulcrum, and you use your other hand to pull up on a load of dirt.
Answer:
The spring force constant is
.
Explanation:
We are told the mass of the ball is
, the height above the spring where the ball is dropped is
, the length the ball compresses the spring is
and the acceleration of gravity is
.
We will consider the initial moment to be when the ball is dropped and the final moment to be when the ball stops, compressing the spring. We supose that there is no friction so the initial mechanical energy
is equal to the final mechanical energy
:

Initially there is only gravitational potential energy because the force of the spring isn't present and the speed is zero. In the final moment there is only elastic potential energy because the height is zero and the ball has stopped. So we have that:

If we manipulate the equation we have that:




<u> Ohms law: </u> This law relates voltage difference between two points. Mathematically, the law states that V=IR;
Where
V = voltage difference ; in volts
I = Current ; in Amperes
R = Resistance ; in ohms
<u>1. Answer : </u> given that R = 10 ; V= 12 V ; I = ?
From ohms law, I = V/R
= 12/10
= 1.2 Amp.
<u>2. Answer:</u> given that R = 10 ; V= ? ; I = 5
From ohms law, V = IR
= 10×5 = 50 V
<u>3 . Answer:</u> given that R = ? ; V= 120 ; I = 5
From ohms law, R = V/I
= 120/5
= 24 Ω
<u>4 . Answer:</u> given that R = ? ; V= 10 ; I = 20
From ohms law, R = V/I
= 10/20
= 0.5 Ω
<u>5 . Answer:</u> given that R = 480 ; V= 24 ; I = ?
From ohms law, I = V/R
= 24/480
= 0.05 A
<u>6. Answer:</u> given that R = 150 ; V= ? ; I = 1
From ohms law, V = IR
= 1 × 150
= 150 V