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Ymorist [56]
3 years ago
13

What is the new kinetic energy of the 1900 kg ship on the right moving at 4 m/s?

Physics
2 answers:
Kay [80]3 years ago
8 0

Answer:

15,200J

Explanation:

The equation is 1/2 x m x v², where m= mass and v= velocity.

Elis [28]3 years ago
7 0

Answer:

soi nuevo

Explanation:me  regalan puntos

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In describing a vector, what must you describe besides the magnitude?
Anton [14]

Answer:

Direction

Explanation:

A vector is a geometrical representation of physical quantity. It has a particular direction with a specific magnitude.

In the geometry of space whether it is two dimensional or three dimensional the vector quantity has a specific direction. Such as a stone is thrown with a velocity in a particular direction.

The path of the stone in three-dimension shows its direction and speed is its magnitude.  

Hence, the velocity of stone has two property magnitude mentioned as speed and particular direction.

On writing the mathematical expressions for vectors, it is denoted by arrow mark on its top as shown below.

                          \vec{A}

7 0
3 years ago
A car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 1.85 m/s2
Tasya [4]

Answer:

Coefficient of friction = 0.836

Explanation:

If v be the speed after one quarter of the circular path

v² = 2as = 2 x 1.85 x 2πr/4 ; v²/r = 1.85 x 3.14 = 5.8

tangential acceleration = 5.8 m/s²

radial acceleration = v² /r = 5.8

total acceleration = √2 x 5.8

m x√2 x 5.8 = m x g xμ

μ = √2 x 5.8 / 9.8 = 0.836

7 0
3 years ago
A proton is moving at 425 m/s. (a) How much work must be done on it to stop it? (A proton has a mass of 1.67×10−27 kg.) (b) Assu
Tpy6a [65]

Answer:

a)1.51*10^-22joules b) 1.89*10^-7m

Explanation:

Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules

b) net force acting to stop the proton = 8.01*10^-16

Work done needed to stop the proton = net force acting opposite the motion * distance

Distance covered = need work done/ net force

Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m

8 0
4 years ago
A boat is subject to hydrodynamic drag forces of F = 40v 2 [N] where v is the magnitude of velocity in [m/s]. The boat’s mass is
stepladder [879]

Answer:

It has moved a distance, S = 25.9 m

Explanation:

F = 40 v²........(1)

F = mv\frac{dv}{dS}.........(2)

Equating (1) and (2)

-mv\frac{dv}{dS} = 40 v^2\\\\v\frac{dv}{dS} = \frac{-40 v^2}{m}  \\\\m = 450 kg\\v\frac{dv}{dS} = \frac{-40 v^2}{450}\\\\ \frac{dv}{v} = \frac{40}{450} dS\\

Integrate both sides:

v_1 = 1, v_2 = 10

\int\limits^{10}_1 {\frac{1}{v} } \, dv = \frac{-40}{450}  \int\limits^S_0  \, dS \\\\ln\frac{1}{10} = \frac{-40}{450} (S-0)\\\\S = \frac{-40}{450} ln(0.1)\\\\S = 25.9 m.

6 0
3 years ago
The mertric unit of electrical power is the _____. A. watt B.volt C.ampere D.ohm
sladkih [1.3K]

Answer:

A - Watt

Explanation:

Watt is the unit of electrical power in a metric system, expressed in terms of energy per second, equal to the work done at a rate of 1 joule per second is

power formula is P = V × I,

                                              where V is the voltage in a circuit

                                                      I is the current flowing through that circuit.

In the SI (metric) system, the units of power are watts.

5 0
3 years ago
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